如何使用另一个键的值（整数）拆分字典值答案

【问题标题】：How to split dictionary values using the another key's values(integer)如何使用另一个键的值（整数）拆分字典值
【发布时间】：2016-11-10 19:34:38
【问题描述】：

我做了字典。像这样；

output = {}
output['epoch time'] = obstimes
output['Number of satellites'] = numsat
output['OK flag'] = ok_flag
output['PRN'] = sats
output['Observation'] = result
output['Number of each data'] = a

我必须使用另一个键的值来拆分字典值。我举个例子。

{...],
'Observation': ['22527689.086 7', None, '-578290.975 7', '-410051.96348', '22527682.94948', 
                '20593906.672 7', None, '-142315.266 7', '-103992.19948', '20593902.01648',
                '22312367.273 6', '22312363.496 9', '-573672.801 6', '-426591.952 9', '22312363.52047', 
                '24649943.453 3', None, '-696710.409 3', '-499047.10745', '24649943.55545', 
                '21574180.359 7', None, '-440212.809 7', '-323130.81248', '21574175.09448', 
                '20159532.789 7', None, '35621.205 7', '26243.45049', '20159527.23449', 
                '24435415.719 6', '24435413.602 9', '417737.346 6', '319304.620 9', '24435413.80147', 
                '23108319.461 5', None, '344109.572 5', '249072.03046', '23108315.90646', 
                '21789481.414 7', None, '326180.505 7', '238895.05548', '21789474.12548', 
                '21975436.727 7', None, '277875.380 7', '205734.181 8', '21975443.121 8', 
                '19981973.117 9', None, '-127270.254 9', '-94211.274 9', '19981980.414 9', 
                '21682862.406 6', None, '242033.680 6', '179454.101 8', '21682869.020 8', 
                '20647552.734 7', None, '-446216.926 7', '-329944.882 9', '20647562.945 9', 
                '23174371.141 6', None, '-645644.090 6', '-481288.202 8', '23174379.656 8', 
                '21946454.047 6', None, '420271.088 6', '311362.996 8', '21946462.590 8', 
                '21922170.063 8', None, '-124733.763 8', '-92183.249 9', '21922177.883 9'
 ...],...}

我想使用另一个值列表拆分这个“观察”值。

另一个值列表是这样的；

 'Number of each data' = [[80, 80, 80, 80, 80, 80, 80, 80, 80, 
 80, 80, 80, 80, 80, 80, 80, 80, 75, 80, 80, 80, 65, 75, 75, 75, 
 70, 60, 50, 55, 55, 70, 65, 75, 75, 70, 65, 75, 75, 75, 65, 70, 
 70, 75, 75.....]]

我想使用每个“每个数据的数量”值拆分观察值。

我希望这样的输出；

...], 'Observation' : [80 values][80 values][80 values]...}

请为我提供帮助或建议。

【问题讨论】：

标签： python list dictionary for-loop split

【解决方案1】：

您应该遍历“每个数据的数量”列表：

output['ObservationMatrix'] = []
counter = 0
for value in output['Number of each data']:
    output['ObservationMatrix'].append(output['Observation][counter:counter + value])
    counter += value

最后，从你的字典中删除（如果你想的话）输出['Observation']

【讨论】：