循环多维 PHP 数组并显示所有对应的数组

Question

我在这个主题上发现了一个几乎类似的问题Loop Multidimensional PHP arrays 我的数组有点不同但几乎相似：

Array  
    (   
        [size] => int (995)
        [data] => Array
            (
                [0] => Array
                    (
                        [service] => 8000
                        [network] => xxx.xxx.xxx
                    )
            
                [1] => Array
                    (
                        [service] => 9000
                        [network] => xxx.xxx.xxx
                    )
                [2] => Array
                    (
                        [service] => 9500
                        [network] => xxx.xxx.xxx
                    )
            )    
    )

我想检查所有service的值，以查看用户输入的数字是否有效并存在，并显示对应的network

这是我天真的尝试：

$record = NULL;

// let's assume $x as this array here
foreach($record in $x['data']){
    if($record['service'] == $bus){
        break;
    }
}

if($record){
    // record found
    var_dump($record);
}else{
    echo "Not found";
}

Answer 1

只是为了好玩，假设 service 是唯一的：

$services = array_column($x['data'], null, 'service');

if(isset($services[$bus]) {
    echo $services[$bus]['network'];
} else {
    echo "Not found";
}

• 提取一个数组并用service索引它
• 现在您可以通过$services[$bus] 访问它。 $services[8000]['network']。

Answer 2

几乎正确：

forEach 语法正好相反：forEach(<array> as $iterator) 哦，您需要处理对 $reslt 变量的赋值（由于某种原因我将其重命名为 $found ）有点不同

 $found=NULL;
    // let's assume $x as this array here
    foreach($x['data'] as $record ){
        if($record['service'] == $bus){
            $found=$record['service'];
        }
    }

    if($found != NULL){
        // record found
        var_dump($record);
    }else{
        echo "Not found";
    }

Answer 3

添加到 Johnathon Heindl：（抱歉我还不能回复）。

将 $found 设为一个数组可能很有用，以防您发现相同的服务具有不同的网络。

$found=[];
// let's assume $x as this array here
foreach($x['data'] as $record ){
   if($record['service'] == $bus){
       //appends to $found
       $found[]=$record['service'];
   }
}
if(!empty($found){
   // record(s) found
   var_dump($record);
}else{
   echo "Not found";
}

Answer 4

如果我没看错你的问题，应该是这样的：

// For the sake of the example, first I reconstructed your array:
$ar1 = array("service" => 8000, "network" => "111.111.111");
$ar2 = array("service" => 9000, "network" => "222.222.222");
$ar3 = array("service" => 9500, "network" => "333.333.333");
$x = array("size" => 995,
        "data" => array($ar1,$ar2,$ar3));

$record = NULL;
$bus = 9000;

for($n = 0; $n < count($x["data"]); $n++){
    $checkService = $x["data"][$n];
    if($checkService["service"] == $bus){
        $record = $checkService["network"];
    }
}

if ($record) {
    // If record found:
    echo "Lookup Results for ".$bus.": ".$record;
    // Since we are searching for 9000 in this example, this should output -> Lookup Results for 9000: 222.222.222
} else {
    echo "Record not found";
}

此代码可以进一步简化，但我不确定您究竟需要什么。

您可以通过this example查看最终结果。

Answer 5

$found_record = NULL;
// let's assume $x as this array here
foreach($record in $x['data']){
if($record['service'] == $bus){
     $found_record = $record['service'];
      break;
    }
  }
 if($found_record){
   // record found
   var_dump($record);
  }else{
    echo "Not found";
}