【问题标题】:Graphql no resolver definied for interface/union - javaGraphql没有为接口/联合定义解析器 - java
【发布时间】:2019-06-12 14:21:16
【问题描述】:

我在graphql 中使用此方法添加解析器时遇到问题:

@RestController
@RequestMapping("/api/dictionary/")
@RequiredArgsConstructor(onConstructor = @__(@Autowired))
public class DictionaryController {
    @Value("classpath:items.graphqls")
    private Resource schemaResource;
    private GraphQL graphQL;
    private final DictionaryService dictionaryService;

    @PostConstruct
    public void loadSchema() throws IOException {
        File schemaFile = schemaResource.getFile();
        TypeDefinitionRegistry registry = new SchemaParser().parse(schemaFile);
        RuntimeWiring wiring = buildWiring();
        GraphQLSchema schema = new SchemaGenerator().makeExecutableSchema(registry, wiring);
        graphQL = GraphQL.newGraphQL(schema).build();
    }

private RuntimeWiring buildWiring() {
    DataFetcher<List<DictionaryItemWithParentDto>> fetcher6 = dataFetchingEnvironment -> dictionaryService.getClaimSubType();

        return RuntimeWiring.newRuntimeWiring()
                .type("Query", typeWriting ->
                   typeWriting
                    .dataFetcher("getClaimSubType", fetcher6)
                    )
                .build();
    }


public List<DictionaryItemWithParentDto> getClaimSubType() {
    return dictionaryService.getClaimSubType();
   }
  }

items.graphqls文件内容:

type Query {
    getClaimSubType: [DictionaryItemWithParentDto]
}

type DictionaryItemWithParentDto {
    code: String!
    name: String
    parents: [DictionaryItemDto]
}

type DictionaryItemDto {
    code: String!
    name: String
    description: String
}

在 java 中,我有 Vehicle 接口和两个实现它的类:AirplaneCar。当我将这一行添加到架构时:

union SearchResult = Airplane | Car

我收到以下错误:

There is no type resolver defined for interface / union 'Vehicle' type, There is no type resolver defined for interface / union 'SearchResult' type]}

我不知道如何处理它。

如果我添加:

interface Vehicle {
    maxSpeed: Int
}

type Airplane implements Vehicle {
    maxSpeed: Int
    wingspan: Int
}

type Car implements Vehicle {
    maxSpeed: Int
    licensePlate: String
}

我收到以下错误:

errors=[There is no type resolver defined for interface / union 'Vehicle' type]

如何使用我的方法处理这些错误?有没有其他的处理方法?

编辑

我猜添加这些代码行可以解决部分问题:

TypeResolver t =  new TypeResolver() {
    @Override
    public GraphQLObjectType getType(TypeResolutionEnvironment env) {
        Object javaObject = env.getObject();
        if (javaObject instanceof Car) {
            return env.getSchema().getObjectType("Car");
        } else if (javaObject instanceof Airplane) {
            return env.getSchema().getObjectType("Airplane");
        } else {
            return env.getSchema().getObjectType("Car");
        }
    }
};

并添加到RuntimeWiring builder 这个:

            .type("Vehicle", typeWriting ->
                    typeWriting
                            .typeResolver(t)
            )


    @PostMapping("getVehicle")
    public ResponseEntity<Object> getVehicleMaxSpeed(@RequestBody String query) 
   {
        ExecutionResult result = graphQL.execute(query);
        return new ResponseEntity<Object>(result, HttpStatus.OK);
    }

要求时:

query {
    getVehicle(maxSpeed: 30) {
        maxSpeed

    }
}

我得到了maxSpeed,但是当我添加wingspan 时出现错误

Field 'wingspan' in type 'Vehicle' is undefined @ 'getVehicle/wingspan'",

我加了

getVehicle(maxSpeed: Int): Vehicle

graphqls 文件。我认为多态在这里会起作用。

【问题讨论】:

    标签: java graphql graphql-java


    【解决方案1】:

    添加这些代码行可以解决问题:

    TypeResolver t =  new TypeResolver() {
        @Override
        public GraphQLObjectType getType(TypeResolutionEnvironment env) {
            Object javaObject = env.getObject();
            if (javaObject instanceof Car) {
                return env.getSchema().getObjectType("Car");
            } else if (javaObject instanceof Airplane) {
                return env.getSchema().getObjectType("Airplane");
            } else {
                return env.getSchema().getObjectType("Car");
            }
        }
    };
    

    并添加到RuntimeWiring builder 这个:

                .type("Vehicle", typeWriting ->
                        typeWriting
                                .typeResolver(t)
                )
    
    
        @PostMapping("getVehicle")
        public ResponseEntity<Object> getVehicleMaxSpeed(@RequestBody String query) 
       {
            ExecutionResult result = graphQL.execute(query);
            return new ResponseEntity<Object>(result, HttpStatus.OK);
        }
    

    要求时:

    query {
        getVehicle(maxSpeed: 30) {
            maxSpeed
    
        }
    }
    

    我得到了maxSpeed,但是当我添加wingspan 时出现错误

    Field 'wingspan' in type 'Vehicle' is undefined @ 'getVehicle/wingspan'",
    

    我加了

    getVehicle(maxSpeed: Int): Vehicle
    

    graphqls 文件。我认为多态在这里会起作用。

    如果我想要来自子类的字段,我可以这样要求它们:

    query {
        getVehicle(maxSpeed: 10) {
            maxSpeed
            ... on Airplane {
            wingspan
          }
            ... on Car {
            licensePlate
          }
        }
    }
    

    【讨论】:

    • 你是如何编译这行代码的? if (javaObject instanceof Car) { 这个 CAR 类是如何生成的?
    • 正常Java类-手工制作
    • 在不创建 Car 类的情况下有没有通用的方法?
    • @stark 我已经检查了javaObject instanceof Map &amp;&amp; ((Map)javaObject).get("__typename") 并将类型名称直接放入映射值中。你可以做任何你想做的事情来确定 GraphQL 类型名称,给定一个值,它必须是基于具体类的(尽管它是一个非常 Java 惯用的选项)
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