有没有办法通过多个值查找数组元素？ [复制]

Question

我有一个数组：

people = [
  {name: a, group: 1},
  {name: b, group: 2},
  {name: c, group: 3},
  {name: d, group: 2},
  {name: e, group: 3},
  {name: f, group: 1},
  {name: g, group: 1},
];

我需要找到第 2 组和第 3 组中的所有人。 期望的输出：

filteredPeople = [
  {name: b, group: 2},
  {name: c, group: 3},
  {name: d, group: 2},
  {name: e, group: 3},
];

也可能是其他组（用于搜索的组可能会改变）。

我该怎么做？

Answer 1

您可以使用.filter() 和.includes() 方法来获得所需的输出：

const data = [
  {name: 'a', group: 1}, {name: 'b', group: 2}, {name: 'c', group: 3},
  {name: 'd', group: 2}, {name: 'e', group: 3}, {name: 'f', group: 1},
  {name: 'g', group: 1}
];

const groups = [2, 3];

const result = data.filter(({ group }) => groups.includes(group));

console.log(result);

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Answer 2

filter 和 includes 在这里完成工作。我们使用其余运算符（这为我们提供了一个可以应用includes 的数组）。因此，您可以将任意数量的组放入函数调用中，以便在过滤时灵活。

let people = [{name: "a",group:1},{name: "b",group:2},{name: "c",group:3},{name:"d",group:2},{name:"e",group:3},{name:"f",group:1},{name:"g",group:1}];

let filterGroups = (arr, ...groups) => arr.filter(o => groups.includes(o.group));

console.log(filterGroups(people, 2, 3));

Answer 3

使用Array.prototype.filter() 和表达式2 === group || group === 3

const data = [{name: 'a', group: 1}, {name: 'b', group: 2}, {name: 'c', group: 3}, {name: 'd', group: 2}, {name: 'e', group: 3}, {name: 'f', group: 1}, {name: 'g', group: 1}];
const result = data.filter(({ group }) => group === 2 || group === 3);

console.log(result);