【发布时间】:2018-11-13 01:13:01
【问题描述】:
我正在尝试使用以下代码获取 Zillow ID:
from pyzillow.pyzillow import ZillowWrapper, GetDeepSearchResults,GetUpdatedPropertyDetails
address = '1600 Pennsylvania Ave NW, Washington, DC'
zipcode = '20006'
zillow_data = ZillowWrapper('API Key')
deep_search_response = zillow_data.get_deep_search_results(address,zipcode)
result = GetDeepSearchResults(deep_search_response)
print(result.zillow_id)
关于为什么上述方法不起作用的任何想法?这是错误:
ZillowFail Traceback (most recent call last)
<ipython-input-12-7f34d0e7b6f0> in <module>()
3 zipcode = '60053'
4 zillow_data = ZillowWrapper('API Key')
----> 5 deep_search_response = zillow_data.get_deep_search_results(address,zipcode)
6 result = GetDeepSearchResults(deep_search_response)
7 print(result.zillow_id)
/home/mfranzidis/pyenvs/numeric/lib/python2.7/site-packages/pyzillow/pyzillow.pyc in get_deep_search_results(self, address, zipcode)
29 'zws-id': self.api_key
30 }
---> 31 return self.get_data(url, params)
32
33 def get_updated_property_details(self, zpid):
/home/mfranzidis/pyenvs/numeric/lib/python2.7/site-packages/pyzillow/pyzillow.pyc in get_data(self, url, params)
62 requests.exceptions.TooManyRedirects,
63 requests.exceptions.Timeout):
---> 64 raise ZillowFail
65
66 try:
ZillowFail:
【问题讨论】:
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请详细说明“不起作用”是什么意思!
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当然,我现在将其添加到问题中。不幸的是,这个错误对我没有任何意义,希望它对你有用:)