【发布时间】：2016-04-01 03:47:33
【问题描述】：
希望构建一个 tcp 侦听器，该侦听器将从连接中读取信息并以一些数据进行响应。
我的程序在单行输入上运行，但是当我发送多行时它不起作用。
这是我使用的代码
try {
Socket clientConnection = null;
clientConnection = serverSocket.accept();
clientConnection.setSoTimeout(5 * 1000);
String tmpLine=null;
BufferedReader inFromClient = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
for (tmpLine = inFromClient.readLine(); tmpLine != null; tmpLine = inFromClient.readLine()) {
searchLine += tmpLine;
logMsg = "DBUG : T" + threadName + " readline : " + searchLine;
stubLog.addMessage(logMsg, coreProperties.getLogger(),"DEBUG");
}
} catch (Exception e) {
logMsg = "ERRR : T" + threadName + " : tcpStubWorker: error in getting data : " + e.getMessage();
stubLog.addMessage(logMsg, coreProperties.getLogger(),"ERROR");
e.printStackTrace();
}
当我从安全带发送此消息时：
String logonMsg = "msg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021\n"
+ "bit 007: 1012165507 \n"
+ "bit 011: 498432 \n"
+ "bit 033: (11)59501100554 \n"
+ "bit 070: 001 \n"
+ "bit 100: (11)59503646554 \n";
我在日志中得到了这个：
DEBUG com.stubby.tcp.tcpStub - 14:33:43:494 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021
DEBUG com.stubby.tcp.tcpStub - 14:33:43:509 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021bit 007: 1012165507
DEBUG com.stubby.tcp.tcpStub - 14:33:43:510 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021bit 007: 1012165507 bit 011: 498432
DEBUG com.stubby.tcp.tcpStub - 14:33:43:534 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021bit 007: 1012165507 bit 011: 498432 bit 033: (11)59501100554
DEBUG com.stubby.tcp.tcpStub - 14:33:43:552 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021bit 007: 1012165507 bit 011: 498432 bit 033: (11)59501100554 bit 070: 001
DEBUG com.stubby.tcp.tcpStub - 14:33:43:603 - DBUG : T00000026 readline : nullmsg: 0800 P3A^SNAT2 >>> S3A^SNAT204 15/10/12 16:55:07.00 rec: 001021bit 007: 1012165507 bit 011: 498432 bit 033: (11)59501100554 bit 070: 001 bit 100: (11)59503646554
ERROR com.stubby.tcp.tcpStub - 14:33:48:627 - ERRR : T00000026 : tcpStubWorker: error in getting data : Read timed out
知道为什么 for 循环无法识别 tmpLine != null 吗？
我想我可以减少超时并将该错误作为警告，但这听起来不太正确！
谢谢。
感谢反馈，对端正在使用此代码发送数据
Socket clientSocket = new Socket("10.52.88.102", 8888);
DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream());
BufferedReader inFromServer = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
outToServer.writeBytes(logonMsg + '\n');
modifiedSentence = inFromServer.readLine();
System.out.println("From server: \"" + modifiedSentence +"\"");
clientSocket.close();
但仍然出现错误:(所以我怀疑我没有正确关闭连接？？
【问题讨论】：
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您不需要初始化在下一行分配的变量。