【发布时间】:2019-02-14 01:02:53
【问题描述】:
我正在尝试将订单表过滤到每个人第一年的订单价值。
我的数据采用以下格式,其中每一行代表一个订单,但我添加了客户级别的列来表示他们的第一个订单日期 (Recruitment Date) 以及标志着每个客户以来一年的日期第一次订购 (1st Year Since Recruitment) 和招聘后的第二年;最后一列是当前订单支付的金额。
Classes ‘tbl_df’, ‘tbl’ and 'data.frame': 1876202 obs. of 6 variables:
$ Brand_Acc : chr "B000000001" "B000000002" "B000000002" "B000000002" ...
$ salesdate : Date, format: "2008-03-10" "2008-02-19" "2008-07-14" "2010-08-25" ...
$ Recruitment Date : Date, format: "2008-03-10" "2008-02-19" NA NA ...
$ 1st Year Since Recruitment: Date, format: "2009-03-10" "2009-02-19" NA NA ...
$ 2nd Year Since Recruitment: Date, format: "2010-03-10" "2010-02-19" NA NA ...
$ TotalDiscount : num 97.9 349.9 184.9 284.9 348.9 ...
我想返回一个数据框,用于捕获每个客户第一年的订单价值。
我尝试了以下方法:
df %>%
group_by(Brand_Acc) %>%
filter(salesdate, between(`Recruitment Date`, `1st Year Since Recruitment`))
但我收到此错误:
Error in filter_impl(.data, quo) : Evaluation error: argument "right" is missing, with no default.
这样做的正确方法是什么?
编辑显示前 5 行的输入:
dput(df)
structure(list(Brand_Acc = c("B000000001", "B000000002", "B000000002",
"B000000002", "B000000006"), salesdate = structure(c(13948, 13928,
14074, 14846, 13934), class = "Date"), ordertype = c("Recruitment",
"Recruitment", "Conversion", "Active Order", "Recruitment"),
actv_channel = c("MainMail", "MainMail", "Outbound-Other",
"MainMail", "MainMail"), TotalDiscount = c(97.87, 349.88,
184.94, 284.94, 348.9), campaignparentid = c("9017", "9017",
"9035", "9557", "9017"), BrandAccount_Brand = c("wp", "wp",
"wp", "wp", "wp"), recrtype = c("STNRD", "STNRD", "STNRD",
"STNRD", "STNRD"), POA_CODE = structure(c(1937L, 2302L, 2302L,
2302L, 466L), .Label = c("0", "200", "800", "801", "804"), class = "factor"),
`Recruitment Date` = structure(c(13948, 13928, NA, NA, 13934
), class = "Date"), `1st Year Since Recruitment` = structure(c(14313,
14294, NA, NA, 14300), class = "Date"), `2nd Year Since Recruitment` = structure(c(14678,
14659, NA, NA, 14665), class = "Date"), `3rd Year Since Recruitment` = structure(c(15043,
15024, NA, NA, 15030), class = "Date")), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -5L))
> ```
【问题讨论】: