Excel在'x'之前和之后替换字符串中的字符

Question

您好，我有一列包含字符串（产品名称）。 现在这些被格式化为 Name LenghtxWidth，例如绿色框 20x30。现在我需要在这个例子中将 20 更改为 30，这样我就得到了 30x20 的绿框，有什么想法可以实现这一点吗？ 谢谢

Answer 1

这里既是公式解决方案，也是使用正则表达式的 VBA 解决方案：

公式

=LEFT(A1,FIND(TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",99)),99)),A1)-1)&
MID(TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",99)),99)),SEARCH("x",TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",99)),99)))+1,99)&
"x"&
LEFT(TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",99)),99)),SEARCH("x",TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",99)),99)))-1)

UDF

Option Explicit
Function RevWL(S As String)
    Dim RE As Object
    Const sPat As String = "(\d+.?\d*)x(\d+.?\d*)"

'If L or W might start with a decimal point, and not a digit,
'Then change sPat to:  (\d*.?\d+)x(\d*.?\d+)

Set RE = CreateObject("vbscript.regexp")
With RE
    .Global = True
    .ignorecase = True
    .Pattern = sPat
    RevWL = .Replace(S, "$2x$1")
End With

End Function

以下是我测试过的数据类型示例：

公式的工作原理是查看最后一个以空格分隔的子字符串 LxW，然后反转 x 之前和之前的部分，然后将所有内容重新连接在一起。

正则表达式模式捕获两个数字（可以是整数或小数，只要以整数开头 - 尽管如果需要可以更改），并将它们反转。

这里是正则表达式（和替换字符串）的更详细说明，并附有教程链接：

(\d+.?\d*)x(\d+.?\d*)

(\d+.?\d*)x(\d+.?\d*)

选项：不区分大小写； ^$ 在换行符处不匹配

• Match the regex below and capture its match into backreference number 1(\d+.?\d*)
  • Match a single character that is a “digit”\d+
    • Between one and unlimited times, as many times as possible, giving back as needed (greedy)+
  • Match any single character that is NOT a line break character.?
    • Between zero and one times, as many times as possible, giving back as needed (greedy)?
  • Match a single character that is a “digit”\d*
    • Between zero and unlimited times, as many times as possible, giving back as needed (greedy)*
• Match the character “x” literallyx
• Match the regex below and capture its match into backreference number 2(\d+.?\d*)
  • Match a single character that is a “digit”\d+
    • Between one and unlimited times, as many times as possible, giving back as needed (greedy)+
  • Match any single character that is NOT a line break character.?
    • Between zero and one times, as many times as possible, giving back as needed (greedy)?
  • Match a single character that is a “digit”\d*
    • Between zero and unlimited times, as many times as possible, giving back as needed (greedy)*

$2x$1

• Insert the text that was last matched by capturing group number 2$2
• Insert the character “x” literallyx
• Insert the text that was last matched by capturing group number 1$1

使用RegexBuddy创建

Answer 2

这是一个适合您的 VBA 解决方案：

Option Explicit

Function Switch(r As Range) As String

Dim measurement As String
Dim firstPart As String
Dim secondPart As String

measurement = Right(r, Len(r) - InStrRev(r, " "))
secondPart = Right(measurement, Len(measurement) - InStr(1, measurement, "x"))
firstPart = Left(measurement, InStr(1, measurement, "x") - 1)
Switch = Left(r, InStrRev(r, " ") - 1) & " " & secondPart & "x" & firstPart

End Function

您可以将其粘贴到VBE (Visual Basic Editor) 的常规模块中，并将其用作常规函数/公式。如果您的值在单元格 A1 中，则在单元格 B1 中键入 =Switch(A1)。希望对您有所帮助！

Answer 3

好的，所以使用 VBA 确实更容易，但如果您只需要一些公式，您可以使用一些列来拆分文本，然后连接您的单元格。

这是一个小例子：

当然 B1-4 是可选的。这里只是为了让一些更易读的东西，但你可以只使用一个公式

=CONCATENATE(LEFT(A1, SEARCH(" ",A1,1)-1)," ",RIGHT(RIGHT(A1,LEN(A1)-SEARCH(" ",A1,1)),LEN(RIGHT(A1,LEN(A1)-SEARCH(" ",A1,1)))-SEARCH("x",RIGHT(A1,LEN(A1)-SEARCH(" ",A1,1)),1)),"x",LEFT(RIGHT(A1,LEN(A1)-SEARCH(" ",A1,1)), SEARCH("x",RIGHT(A1,LEN(A1)-SEARCH(" ",A1,1)),1)-1))

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如果您的名字中有几个空格，您可以使用这个公式来搜索文本中的最后一个空格

=CONCATENATE(LEFT(A1, SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))-1)," ",RIGHT(RIGHT(A1,LEN(A1)-SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))),LEN(RIGHT(A1,LEN(A1)-SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))))-SEARCH("x",RIGHT(A1,LEN(A1)-SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))),1)),"x",LEFT(RIGHT(A1,LEN(A1)-SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))), SEARCH("x",RIGHT(A1,LEN(A1)-SEARCH("^^",SUBSTITUTE(A1," ","^^",LEN(A1)-LEN(SUBSTITUTE(A1," ",""))))),1)-1))