从 JavaScript / jQuery 中的键值表替换多个对象值

Question

我试图弄清楚如何使用键值表替换多个对象值。

我一直在尝试从对常规字符串执行此操作的函数中学习，并使其适用于对象（特别是对象值）。我想也许有办法将这种 (https://stackoverflow.com/a/15604206/2458671) 函数与下面的 replaceValue 函数合并。

var settings = {
  pushItems: {
    "[make_up_policy_attributes][staff_allowed]": true,
    "[make_up_policy_attributes][default_issued_plan_product_id]": "{RPPA}",
    "[make_up_policy_attributes][issued_plan_product_expires]": true,
    "[make_up_policy_attributes][issued_plan_product_duration_months]": 0,
    "[make_up_policy_attributes][issued_plan_product_duration_weeks]": 0,
    "[make_up_policy_attributes][issued_plan_product_duration_days]": 30
  }
}

replaceValue(settings.pushItems, "{RPPA}", 12345 );

function replaceValue(obj, findvalue, replacewith) {
  for (var key in obj) {
    var value = obj[key];
    if (value === findvalue) {
      obj[key] = value.replace(findvalue, replacewith);
    }
  }
}

基本上我想使用一个对象 { searchForValue1: replaceWithValue1, searchForValue2: replaceWithValue2 } 所以如果在 settings.pushItems 对象中找到多个东西，我可以替换它们。

Answer 1

您可以通过更改 if 语句来做到这一点，如下面的代码：

var settings = {
  pushItems: {
    "[make_up_policy_attributes][staff_allowed]": true,
    "[make_up_policy_attributes][default_issued_plan_product_id]": "{RPPA}",
    "[make_up_policy_attributes][issued_plan_product_expires]": true,
    "[make_up_policy_attributes][issued_plan_product_duration_months]": 0,
    "[make_up_policy_attributes][issued_plan_product_duration_weeks]": 0,
    "[make_up_policy_attributes][issued_plan_product_duration_days]": 30,
    "exampleValue1": "abc1",
    "exampleValue2": "abc2",
    "exampleValue3": "abc3",
  }
}

var replaceObject = {
  "{RPPA}": 12345,
  "abc2": "newValue2",
  true: false
}

replaceValue(settings.pushItems, replaceObject);

function replaceValue(obj, replaceObject) {
  for (var key in obj) {
    var value = obj[key];
    if (replaceObject.hasOwnProperty(value)) obj[key] = replaceObject[value];
  }
}

console.log(settings.pushItems);

希望这会有所帮助！

编辑：更新 if 条件。