【问题标题】:Jupyter failed to start kernelJupyter 无法启动内核
【发布时间】:2019-12-13 02:07:47
【问题描述】:

所以我刚刚安装了 anaconda 3 并在 anaconda 提示符下运行“jupyter notebook”,这会打开 jupyter。但是,当我打开一个新的 python 3 笔记本时,由于内核错误“无法启动内核”,我无法运行任何代码,并显示以下错误消息

Traceback (most recent call last):
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\web.py", line 1699, in _execute
    result = await result
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Users\Janko\Anaconda3\lib\site-packages\notebook\services\sessions\handlers.py", line 72, in post
    type=mtype))
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Users\Janko\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 88, in create_session
    kernel_id = yield self.start_kernel_for_session(session_id, path, name, type, kernel_name)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Users\Janko\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 101, in start_kernel_for_session
    self.kernel_manager.start_kernel(path=kernel_path, kernel_name=kernel_name)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Users\Janko\Anaconda3\lib\site-packages\tornado\gen.py", line 209, in wrapper
    yielded = next(result)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\notebook\services\kernels\kernelmanager.py", line 168, in start_kernel
    super(MappingKernelManager, self).start_kernel(**kwargs)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\jupyter_client\multikernelmanager.py", line 110, in start_kernel
    km.start_kernel(**kwargs)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\jupyter_client\manager.py", line 240, in start_kernel
    self.write_connection_file()
  File "C:\Users\Janko\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 547, in write_connection_file
    kernel_name=self.kernel_name
  File "C:\Users\Janko\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 212, in write_connection_file
    with secure_write(fname) as f:
  File "C:\Users\Janko\Anaconda3\lib\contextlib.py", line 112, in __enter__
    return next(self.gen)
  File "C:\Users\Janko\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 102, in secure_write
    with os.fdopen(os.open(fname, open_flag, 0o600), mode) as f:
PermissionError: [Errno 13] Permission denied: 'C:\\Users\\Janko\\AppData\\Roaming\\jupyter\\runtime\\kernel-624a372e-0a69-4eda-8068-85cfa1e7c4bd.json'

我尝试用谷歌搜索,但找不到解决方法。请记住,我对内核、环境和我在对类似问题的回复中读到的其他术语不太熟悉,因此我的故障排除能力相当有限(抱歉)。这是我的 kernels.json 文件(其中确实包含 python 可执行文件的正确路径),对类似问题的响应通常与该文件相关联。我感到困惑的另一件事是文件路径有双反斜杠,但如果我改为单反斜杠,jupyter 会说找不到内核。

{
 "argv": [
  "C:\\Users\\Janko\\Anaconda3\\python.exe",
  "-m",
  "ipykernel_launcher",
  "-f",
  "{connection_file}"
 ],
 "display_name": "Python 3",
 "language": "python"
}

谢谢!

【问题讨论】:

  • 尝试以管理员身份运行
  • @zRAA 哇,它成功了,谢谢!但是,jupyter 主页现在显示了大约 4500 个不同的文件和文件夹(大量的 .dll 文件),这些都不是我期望找到的常规文档/桌面/计算机内容。这让我的笔记本电脑变得非常慢。就像需要一分钟才能向下滚动一英寸慢。如果我关闭所有内容并再次运行(不是以管理员身份),我会看到所有正常文件夹,但随后我再次收到内核错误...

标签: python jupyter-notebook anaconda kernel jupyter


【解决方案1】:

堆栈跟踪的最后一行告诉您 Jupyter 无法写入哪个目录:

Permission denied: 'C:\\Users\\Janko\\AppData\\Roaming\\jupyter\\runtime\\kernel-624a372e-0a69-4eda-8068-85cfa1e7c4bd.json'

要么向运行 Jupyter 的用户授予写入该目录的权限,要么将环境变量 JUPYTER_RUNTIME_DIR 设置为可写目录。

https://jupyter.readthedocs.io/en/latest/projects/jupyter-directories.html

【讨论】:

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