【发布时间】：2016-09-30 21:14:55
【问题描述】：
我正在运行一个代码，该代码采用一个整数列表和一个字符串列表，并分别将数组的大小增加到适当的大小，然后以不同的方法对数组进行排序，同时还找到一个重复。在我运行对数组进行排序并查找重复项的方法之前，代码都很好。我知道正确的输出应该是什么，并且在 intList 中不应该找到重复项，并且在索引 45788 处的 wordList 中不应该找到重复项。我已经向其他人寻求帮助，执行同样的简单任务，并且具有与他们相同的代码。我必须离开某个地方，但我找不到在哪里。我在命令提示符的输出旁边附上了这两种方法的照片。感谢您的帮助
import java.io.*;
import java.util.*;
public class Lab4
{
static final int INITIAL_CAPACITY = 10;
static final int NOT_FOUND = -1; // indexOfFirstDupe returns this value if no dupes found
public static void main (String[] args) throws Exception
{
// ALWAYS TEST FIRST TO VERIFY USER PUT REQUIRED INPUT FILE NAME ON THE COMMAND LINE
if (args.length < 1 )
{
System.out.println("\nusage: C:\\> java Lab4 <numbers file> <words filename>\n\n"); // i.e. C:\> java Lab4 10000ints.txt 172822words.txt
System.exit(0);
}
String[] wordList = new String[INITIAL_CAPACITY];
int[] intList = new int[INITIAL_CAPACITY];
int wordCount = 0, intCount=0;
Scanner intFile = new Scanner( new File(args[0]) );
BufferedReader wordFile = new BufferedReader( new FileReader(args[1]) );
// P R O C E S S I N T F I L E
while ( intFile.hasNextInt() ) // i.e. while there are more ints in the file
{
if ( intCount == intList.length )
intList = upSizeArr( intList );
intList[intCount++] = intFile.nextInt();
} //END WHILE intFile
//close intfile
intFile.close();
//output text with variables
System.out.format( "%s loaded into intList array. size=%d, count=%d\n",args[0],intList.length,intCount );
int dupeIndex = indexOfFirstDupe( intList, intCount );
if ( dupeIndex == NOT_FOUND )
{
System.out.format("No duplicate values found in intList\n");
}
else
{
System.out.format("First duplicate value in intList found at index %d\n",dupeIndex);
}
// P R O C E S S S T R I N G F I L E
while ( wordFile.ready() ) // i.e. while there is another line (word) in the file
{
if ( wordCount == wordList.length )
wordList = upSizeArr( wordList );
wordList[wordCount++] = wordFile.readLine();
} //END WHILE wordFile
//closing wordfile
wordFile.close();
//output text again with variables
System.out.format( "%s loaded into word array. size=%d, count=%d\n",args[1],wordList.length,wordCount );
dupeIndex = indexOfFirstDupe( wordList, wordCount );
if ( dupeIndex == NOT_FOUND )
{
System.out.format("No duplicate values found in wordList\n");
}
else
{
System.out.format("First duplicate value in wordList found at index %d\n",dupeIndex);
}
}
// --------------------------------------------------------------------------------------------------------------------------------
// method to double size of string array
static String[] upSizeArr( String[] fullArr )
{
int length = fullArr.length;
//creating a new array of double size
String[] upsizearr = new String[length*2];
//this for loop assigns each old variable in fullArr
//and assigns it to the new larger array, upsizearr
for(int i = 0; i<length-1; i++)
{
upsizearr[i] = fullArr[i];
}
return upsizearr;
}
// method to double size of int array
static int[] upSizeArr( int[] fullArr )
{
int length = fullArr.length;
//creating new array of double size
int[] upsizearr = new int[length*2];
//this loop does the same as in upSizeArr method,
//assigning all values to new bigger array
for(int i = 0; i<length-1; i++)
{
upsizearr[i] = fullArr[i];
}
return upsizearr;
}
// use Arrays.sort() before scanning for dupe
static int indexOfFirstDupe( int[] arr, int count )
{
Arrays.sort(arr);
int value = NOT_FOUND;
for(int i = (arr.length - count); i < count; i++)
{
if(arr[i] == arr[i-1])
{
value = i;
break;
}
}
return value;
}
// use Array.sort() before scanning for dupe
static int indexOfFirstDupe( String[] arr, int count )
{
Arrays.sort(arr);
int value = NOT_FOUND;
for(int i = (arr.length - count); i < count; i++)
{
if(arr[i] == arr[i-1])
{
value = i;
break;
}
}
return value;
}
} // END CLASS
[] []2
【问题讨论】：
-
如果它“运行错误”它不能是“有效的代码”，反之亦然
-
将您的代码添加到问题中而不是图片中。
-
您显示了异常（在图片中而不是复制和粘贴），然后甚至没有显示它所引用的行（第 144 行，在 indexOfFirstDupe 内）...
-
@TimeToCode 和 jonhopkins，我的错。我认为我的屏幕截图比它捕获的更多。我粘贴了我的代码。