【发布时间】:2014-02-01 23:07:54
【问题描述】:
这是用于离散化有限差分格式的一维扩散方程的数字代码。获得每个时间步的速度,我想对此解决方案进行动画处理,以便可视化速度相对于扩散时间的演变。任何帮助,将不胜感激。谢谢!
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D ##library for 3d projection plots
from matplotlib import cm ##cm = "colormap" for changing the 3d plot color palette
###variable declarations
nx = 31
ny = 31
nt = 17
nu=.05
dx = 2.0/(nx-1)
dy = 2.0/(ny-1)
sigma = .25
dt = sigma*dx*dy/nu
x = np.linspace(0,2,nx)
y = np.linspace(0,2,ny)
u = np.ones((ny,nx)) ##create a 1xn vector of 1's
un = np.ones((ny,nx)) ##
###Assign initial conditions
u[.5/dy:1/dy+1,.5/dx:1/dx+1]=2 ##set hat function I.C. : u(.5<=x<=1 && .5<=y<=1 ) is 2
fig = plt.figure()
ax = fig.gca(projection='3d')
X,Y = np.meshgrid(x,y)
surf = ax.plot_surface(X,Y,u[:], rstride=1, cstride=1, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
plt.show()
ax.set_xlim(0,2)
ax.set_ylim(0,2)
ax.set_zlim(1,2.5)
#ax.zaxis.set_major_locator(LinearLocator(5))
###Run through nt timesteps
u[.5/dy:1/dy+1,.5/dx:1/dx+1]=2
for n in range(nt+1):
un[:] = u[:]
u[1:-1,1:-1]=un[1:-1,1:-1]+nu*dt/dx**2*(un[2:,1:-1]-2*un[1:-1,1:-1]+un[0:-2,1:-1])+nu*dt/dy**2* (un[1:-1,2:]-2*un[1:-1,1:-1]+un[1:-1,0:-2])
u[0,:]=1
u[-1,:]=1
u[:,0]=1
u[:,-1]=1
fig = plt.figure()
ax = fig.gca(projection='3d')
surf = ax.plot_surface(X,Y,u[:], rstride=1, cstride=1, cmap=cm.coolwarm,
linewidth=0, antialiased=True)
ax.set_zlim(1,2.5)
plt.show()
【问题讨论】:
标签: python animation matplotlib mayavi