SQL Server 2008：按条件选择成员分组

Question

我有一张桌子

CREATE TABLE #tblA (mem_id int, type varchar(20), address1 varchar(20),group_id int)

insert into #tblA (mem_id, type, address1,group_id)
values (1,'self','abc St',1),
       (2,'Child','abc St',1),
       (3,'Child','xyz st',1),
       (4,'spouse','pqr st',1),
       (5,'Child','abc St',1),
       (6,'Child','xyz st',1),

       (7,'self','mno st',2),
       (8,'Child','def St',2),
       (9,'Child','def st',2),

       (10,'self','loi st',3),
       (11,'Child','loi St',3),
       (12,'Child','ewr st',3)

       (13,'self','ooo st',NULL),

所以，我要选择：

1. 对于每个组，选择“self”。
2. 如果没有组，请选择 self。
3. 如果其他人住在与自己不同的地址，请选择那些 成员。
4. 如果多个成员居住在不同的地址，请选择 1 个居住的成员 在不同的地址

所以预期的结果：

   (1,'self','abc St',1),
   (3,'Child','xyz st',1),
   (4,'spouse','pqr st',1),
   (7,'self','mno st',2),
   (8,'Child','def St',2),
   (10,'self','loi st',3),
   (12,'Child','ewr st',3)
   (13,'self','ooo st',NULL),

谢谢

我的代码：不工作：

select  
   mem_id
from 
   (select 
        a.*,
        RANK() over (partition by group_id order by AddressCnt DESC) as AddressRank
    from 
        (select 
             a.*,
             (case when max(address1) over (partition by group_id) = min(address1) over (partition by group_id)
              then 1 else 0
              end) as AddressSame,
             count(*) over (partition by group_id, address1) as AddressCnt
         from #tblA a) a
   ) a
where 
   (AddressSame = 1 or type in ('Self') or
    (AddressRank > 1 OR  type in ('Self') or group_id is null 

Answer 1

这里有一个解决方案。

• 创建一个识别“自我”记录的 CTE。
• 创建另一个 cte，通过从 self 到 tableA 的连接来识别“others”
• 使用 row_number 只为另一条记录查找一条记录
• 联合两个 cte 的

WITH self 
     AS (SELECT * 
         FROM   tbla 
         WHERE  type = 'self'), 
     others 
     AS (SELECT a.mem_id, 
                a.type, 
                a.address1, 
                a.group_id, 
                Row_number() 
                  OVER ( 
                    partition BY a.group_id, a.address1 
                    ORDER BY a.mem_id) rn 
         FROM   self s 
                INNER JOIN tbla a 
                        ON s.group_id = a.group_id 
                           AND s.mem_id <> a.mem_id --Exclude self records
                           AND s.address1 <> a.address1 --Exclude the same address as self) 
SELECT mem_id, 
       type, 
       address1, 
       group_id 
FROM   self 
UNION 
SELECT mem_id, 
       type, 
       address1, 
       group_id 
FROM   others 
WHERE  rn = 1 
ORDER  BY mem_id 

DEMO

Answer 2

这个 MySQL 查询给出了所需的输出：

select * from tblA with type='self' UNION select * from tblA group by address1 没有 address1 (select address1 from tblA where type='self') ORDER by mem_id;