单选按钮的 XSL 逻辑未按预期工作

Question

XSL

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <!--END OF PROLOGUE-->
    <!-- MATCH STATEMENT TO CAPTURE VARIABLE VALUES-->
    <xsl:template match="ECN">
   <input type="radio"
               id="Pre-Design Transfer"
               name="transfer">
               <!--value="Pre-Design Transfer">-->
            <label for="Pre-Design Transfer">Pre-Design Transfer</label>
            <xsl:if test="radiobuttons/prepost='Pre-Design Transfer'">
                <xsl:attribute name="checked">checked</xsl:attribute>
            </xsl:if>
        </input>
        <input type="radio"
            name="transfer"
               value="Post-Design Transfer">
               <!--id="Post-Design Transfer"-->
              
            <label for="Post-Design Transfer">Post-Design Transfer</label>
            <xsl:if test="radiobuttons/prepost='Post-Design Transfer'">
                <xsl:attribute name="checked">checked</xsl:attribute>
            </xsl:if>
        </input>
        <!--END PRE/POST TRANSFER PARAMETERS  PARAMETERS SECTION OF ECN-->
    </xsl:template>
</xsl:stylesheet>

XML

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type='text/xsl' href='C:\Users\gedkins\Desktop\New folder\Trial.xsl'?>
<ECN>
    <radiobuttons>
        <prepost>Post-Design Transfer</prepost>
    </radiobuttons>
</ECN>

我想获取单选按钮的逻辑以查看 XML 文件中的参数。我无法在 XML 文件加载时选择单选按钮。它们都是未经检查的。我错过了什么？

谢谢。

Answer 1

添加内容后无法创建属性<label>。将xsl:if 移到<label> 上方：

<input type="radio"
      name="transfer"
      value="Post-Design Transfer">
  <xsl:if test="radiobuttons/prepost='Post-Design Transfer'">
      <xsl:attribute name="checked">checked</xsl:attribute>
  </xsl:if>
  <!--id="Post-Design Transfer"-->      
  <label for="Post-Design Transfer">Post-Design Transfer</label>
</input>