从嵌套的 JSON 值创建字典键和值对

Question

我正在尝试通过遍历天气 JSON 文件来创建字典。

我希望键是日期，值是 JSON 中嵌套“小时”中的温度。

combined_temperature_hour = {日期，温度}

当我遍历 JSON 文件时，我可以获得单个项目，但我不知道如何获取这两个值并将它们放在一个（键，值）对中。

combined_temperature_hour = {}

for d in days:
    for hours in d["hours"]:
        hourly = hours.get('datetimeEpoch')
        dia_y_hora = time.strftime('%Y-%m-%d %H:%M:%S', time.localtime(hourly))
        complete_date.append(dia_y_hora)

        h_temp = hours.get('temp')
        hourly_temperature.append(h_temp)

        #combined
        combined = {complete_date, hourly_temperature}
        print(combined)

JSON

"days":[
      {
         "datetime":"2021-01-01",
         "datetimeEpoch":1609484400,
         "tempmax":36.9,
         "tempmin":32.4,
         "temp":34.7,
         "hours":[
            {
               "datetime":"00:00:00",
               "datetimeEpoch":1609484400,
               "temp":32.9,
            },
            {
               "datetime":"01:00:00",
               "datetimeEpoch":1609488000,
               "temp":33.2,
            },
            {
               "datetime":"02:00:00",
               "datetimeEpoch":1609491600,
               "temp":33.2,
            }
         ]
      }

这就是我希望字典在循环后的样子

combined_temperature_hour = {`2021-01-24 05:00:00`: '25.1', `2021-01-24 06:00:00`: '26.2'}

我尝试获取温度和小时的列表，并在循环后将它们组合到字典中，但我注意到我缺少值并且它们可能是不正确的对。

Answer 1

首先将您的 json 作为字典读取到变量 a （我更改了您 json 中一些不匹配的括号）

a = {"days":[
      {
         "datetime":"2021-01-01",
         "datetimeEpoch":1609484400,
         "tempmax":36.9,
         "tempmin":32.4,
         "temp":34.7,
         "hours":[
            {
               "datetime":"00:00:00",
               "datetimeEpoch":1609484400,
               "temp":32.9,
            },
            {
               "datetime":"01:00:00",
               "datetimeEpoch":1609488000,
               "temp":33.2,
            },
            {
               "datetime":"02:00:00",
               "datetimeEpoch":1609491600,
               "temp":33.2,
            }
         ]
       }
    ]
}

然后您可以从以下代码中获得预期的输出：

combined_temperature_hour = {}
for date in a['days']:
  for hour in date['hours']:
    combined_temperature_hour[date['datetime']+' '+hour['datetime']] = hour['temp']