如何找到 .wav 文件的噪声点。我的意思是，不消除噪音，只是在使用 python 发生噪音时

Question

如何找到 .wav 文件的噪声点。我的意思是，不是消除噪音，只是在发生噪音时 我检查了这个分类狗和猫声音的网站

https://www.kaggle.com/nadir89/classification-logistic-regression-svm-on-mfccs/notebook?select=utils.py

但它没有正常工作......

你们能给我一些建议或其他方法来找到 .wav 文件的噪声点

1. 是否可以使用 logreg（机器学习）从声音中找出噪音？不删除..
2. 有没有办法找到噪声点？

Answer 1

试试这个

import noisereduce

temp = noisereduce.reduce_noise(noise_clip=noise_clip,audio_clip=temp,verbose=True)

noise_clip一小部分信号（噪声样本，可能是1s frame_duration）

audio_clip实际音频

 signal, fs = librosa.load(path)
 signln = len(signal)
 avg_energy = np.sum(signal ** 2) / float(signln) #avg_energy of acual signal
f_d = 0.02 #frame duration
perc = 0.01

flag = True
j = 0
f_length = fs * f_d #frame length is `frame per second(fs) * frame_duration(f_d)` 
signln = len(signal)
retsig = []
noise = signal[0:441] # just considering first little part as noise
avg_energy = np.sum(signal ** 2) / float(signln)
while j < signln:
      subsig = signal[int(j): int(j) + int(f_length)]
      average_energy = np.sum(subsig ** 2) / float(len(subsig)) # avg energy of current frame
      if average_energy <= avg_energy: #if enegy of the current frame is less than actual signal then then we can confirm that this frame as silence or noise part
            if flag: #to get first noise or silence appearing on the signal 
                  noise = subsig #if you want to get all the noise frame, then just create a list and append it(noise_list.append(subsig)) and also don't use the flag condition
                  flag = False
            
      else: # if avg energy of current frame is grater than actual signal energy then this frame contain the data 
           retsig.append(subsig) # so you need to add that frame to new variable
      j += f_length