【发布时间】：2013-10-18 16:46:25
【问题描述】：
我正在尝试使用列表或字符向量重命名数据帧 (df) 中的 104 列（我已经尝试过两种方式）。
不是将向量或列表中的 104 个元素分别分配给 104 列，而是将所有 104 个元素分配给第一列，所有其他元素都得到 NA。
关于为什么会出现这种行为以及如何正确执行的任何建议？
> names(df)
[1] "V1" "V2" "V3" "V4" "V5" "V6" "V7" "V8" "V9" "V10" "V11" "V12" "V13" "V14" "V15" "V16" "V17" "V18" "V19" "V20" "V21" "V22" "V23" "V24" "V25" "V26" "V27"
[28] "V28" "V29" "V30" "V31" "V32" "V33" "V34" "V35" "V36" "V37" "V38" "V39" "V40" "V41" "V42" "V43" "V44" "V45" "V46" "V47" "V48" "V49" "V50" "V51" "V52" "V53" "V54"
[55] "V55" "V56" "V57" "V58" "V59" "V60" "V61" "V62" "V63" "V64" "V65" "V66" "V67" "V68" "V69" "V70" "V71" "V72" "V73" "V74" "V75" "V76" "V77" "V78" "V79" "V80" "V81"
[82] "V82" "V83" "V84" "V85" "V86" "V87" "V88" "V89" "V90" "V91" "V92" "V93" "V94" "V95" "V96" "V97" "V98" "V99" "V100" "V101" "V102" "V103" "V104"
> d2 = as.character(strapply(name,"(?<=[0-9]{1}=)(.{2,}?)((?= V[0-9])|(?= $))",perl=TRUE))
> d2
[1] "c(\"ICPSR MEMBER ID NUMBER\", \"CONGRESS\", \"CHAMBER/CLASS\", \"STATE\", \"DISTRICT\", \"PARTY\", \"POL PARTY\", \"FULL NAME\", \"SEX\", \"REGION\", \"STATE BORN ..... \"ICPSR STUDY NUMBER\", \"ICPSR VERSION NUMBER\", \"ICPSR PART NUMBER\")"
> class(d2)
[1] "character"
> colnames(df2) = d2
> head(df2,1)
c("ICPSR MEMBER ID NUMBER", "CONGRESS", "CHAMBER/CLASS", "STATE", "DISTRICT", "PARTY", "POL PARTY", "FULL NAME", "SEX", "REGION", "STATE BORN (ICPSR CODE)", "BORN/REP SAME STATE", "BORN/REP SAME REGION", "ICPSR RELATIVES CODE", "RELATIVES CLLPS", "SE ...
1
1
NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
【问题讨论】：
-
不要将 d2 包裹在
as.character... 您正在从新名称的向量中创建一个字符串... -
所以如果我不这样做，它会生成一个列表。如果我应用该列表，它具有相同的行为。
-
把列表变成向量然后赋值。
?unlist -
?unlist 成功了。感谢迈克尔和贾斯汀的帮助。
标签： r columnname