【发布时间】:2021-06-02 23:32:34
【问题描述】:
我关注了这个问题的答案:Cluster stacked bargraph
使用以下代码:
test <- data.frame(person=c("8.3. The number of people coming to me \n me, who
are who want pizza are too many \n,
and too aggressive.", "group 2", "group 3", "5", "6"),
value1=c(100,150,120,100,100), # Agree
value2=c(25,30,45,100,100) , # Neutral
value3=c(25,30,45,100,100), # Disagree
value4=c(100,120,150,100,100), # Agree
value5=c(10,12,15,100,100), # Neutral
value6=c(50,40,70,100,100)) # Disagree
library(reshape2) # for melt
melted <- melt(test, "person")
melted$cat <- ''
melted[melted$variable == 'value1' | melted$variable == 'value2' | melted$variable == 'value3',]$cat <- "GP"
melted[melted$variable == 'value4' | melted$variable == 'value5'| melted$variable == 'value6',]$cat <- "LW"
melted$gender <- ''
melted[melted$variable %in% sprintf("value%i",c(1,4)),]$gender <- "Agree"
melted[melted$variable %in% sprintf("value%i",c(2,5)),]$gender <- "Disagree"
melted[melted$variable %in% sprintf("value%i",c(3,6)),]$gender <- "Neutral"
p = ggplot(melted, aes(x = cat, y = value, fill = gender))
p + geom_bar(stat = 'identity', position = 'stack') + facet_grid(~ person) +
scale_fill_manual(values = c("orangered","green","dodgerblue2")) +
theme(panel.background = element_rect(fill = 'white'))
我的问题是:
如何固定堆栈的顺序以使中立介于同意和中立之间?反正有没有使图表水平,以便我可以有更广阔的空间来适应这个问题?我还希望在每个条形内显示数字,例如,最左边的红色条形应该写有 100。
我在 R 和 Python 中使用了一些 liekert 库,但我无法对条形进行分组,并且还有其他问题。这个 ggplot 图表是我创建所需图表的最接近的图表,因此如果您的答案与我提供的数字完全可重复,我将不胜感激。
【问题讨论】:
标签: r ggplot2 data-visualization bar-chart visualization