Python中基于分隔符的文本拆分和组合

Question

我有一个包含字符串的列表列表。经过各种正则表达式的工作后，我已将我想用作分隔符的 @@@ 插入到我的字符串中：

[['@@@this is part one and here is part two and here is part three and heres more and heres more'],
 ['this is part one@@@and here is part two and here is part three and heres more and heres more'],
 ['this is part one and here is part two@@@and here is part three and heres more and heres more']
 ['this is part one and here is part two and here is part three@@@and heres more and heres more']
 ['this is part one and here is part two and here is part three and heres more@@@and heres more']]

现在，我需要想出这个：

[['this is part one'],['and here is part two'],['and here is part three'], ['and heres more'], ['and heres more']]  

到目前为止，我的尝试都是臃肿、笨拙且丑陋的。我发现自己分裂、组合和匹配。任何人都可以就此类问题推荐一些一般性建议，以及使用哪些工具来使其易于管理？

编辑请注意！ and heres more 在理想输出中确实出现了两次！

Answer 1

我认为您实际上需要获取紧跟在 @@@ 之后的所有字符，直到下一个 and 或字符串结尾。

>>> [[m] for x in l for m in re.findall(r'@@@(.*?)(?=\sand\b|$)', x[0])]
[['this is part one'], ['and here is part two'], ['and here is part three'], ['and heres more'], ['and heres more']]