【发布时间】:2014-01-30 19:28:47
【问题描述】:
我有一个 data.table,其中有一列包含“Exp 928.6.3 (DMSO)”之类的文本。我想将其解析为“Exp 928”和“6.3”等列。似乎强大的 data.table 应该能够快速完成这项工作,但我不知道如何根据自己的意愿弯曲它。有什么想法吗?
谢谢, 詹姆斯
> dput(head(dat))
structure(list(Experiment = c("Exp 927.1.1 (DMSO)", "Exp 927.1.2 (DMSO)",
"Exp 927.1.3 (DMSO)", "Exp 927.1.4 (DMSO)", "Exp 927.1.5 (DMSO)",
"Exp 927.1.6 (DMSO)"), Conc.1..LP9. = c("Failed", "Failed", "Failed",
"Failed", "Failed", "0.97"), Conc.2..LP11. = c("Failed", "Failed",
"Failed", "Failed", "Failed", "0.87"), Conc.3..LP13. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.81"), Conc.4..LP15. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.76"), Conc.5..LP17. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.58"), Conc.1.uM..µM. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.001"), Conc.2.uM..µM. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.01"), Conc.3.uM..µM. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "0.1"), Conc.4.uM..µM. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "1"), Conc.5.uM..µM. = c("Failed",
"Failed", "Failed", "Failed", "Failed", "10"), exptNo = list(
"927", "1", "1", "927", "1", "1"), sample = c("927", "1",
"2", "927", "1", "2"), replicate = c("927", "1", "3", "927",
"1", "3")), .Names = c("Experiment", "Conc.1..LP9.", "Conc.2..LP11.",
"Conc.3..LP13.", "Conc.4..LP15.", "Conc.5..LP17.", "Conc.1.uM..µM.",
"Conc.2.uM..µM.", "Conc.3.uM..µM.", "Conc.4.uM..µM.", "Conc.5.uM..µM.",
"exptNo", "sample", "replicate"), sorted = "Experiment", class = c("data.table",
"data.frame"), row.names = c(NA, -6L), .internal.selfref = <pointer: 0x0000000000130788>)
【问题讨论】:
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我已添加此数据。
标签: r parsing text data.table