比较两个字符串添加（空格，逗号，点等）C++

Question

大家好，我希望有人可以帮助我，我正在尝试修复我的字符串输出，我得到了一个输出，但它全部混搭成一个长字符串，没有空格等，所以我正在尝试使用旧字符串以前有逗号空格等，并将它们替换为新的。我真的不知道该怎么做我已经在 C++ 中尝试过这个如果我在我的程序中运行下面的代码它会在我身上崩溃我不知道如何修复它。

string input2 = "chq pste uwdn or mfwiejjne
u aaul mvabe mrv po zso, jnp kg co urfrsrvwn,
azh s bmmpd lanmf kuupv chqvw, xf opsh azh ojtfpwb mmhw;
wizi tnaz vgfs imdu i tenn ttijn, a tmnn fav lqe tsfny niw,
jnp paee mpgwe ur lqe niw uogh yuapi.
swd u wzjlx lsee esen pqeun ttijn, fav hnaoi uxmqw vaobtawg epgf,
ddshyizk xaoy xzn vqmdb or xzn mavfrns xg fhqvw chq gjrcwil bizkk;
chqvw vipraphf’w sul m kdrmyij, jnp rgxn m tmapxi yuoi,
efm ehifrns jmul aj lqe xmfwef’w ornsw.
a fixp saiei swd ss fxw, rsj jlieqb nukzc azh vjy
u lwjr xecn wmxwa lmthrns aach xso bogrvb bk xzn stsjn;
wtmdn i exswd ar lqe dssmwmc, ga oz xzn pmzwvezxk prqc,
a qemv ac iz xzn dqih qemvl’b cavw.";


string result = "THELAKEISLEOFINNISFREEIWILLARISEANDGONOWANDGOTOINNISFREEANDASMALLCAB
INBUILDTHEREOFCLAYANDWATTLESMADENINEBEANROWSWILLIHAVETHEREAHIVEFORTH
EHONEYBEEANDLIVEALONEINTHEBEELOUDGLADEANDISHALLHAVESOME
PEACETHEREFORPEACECOMESDROPPINGSLOWDROPPINGFROMTHEVEILSOFTHEMORNINGTOWHERETHE
CRICKETSINGSTHEREMIDNIGHTSALLAGLIMMERANDNOONAPURPLEGLOWANDEVENINGFULLOFTHELINNET
SWINGSIWILLARISEANDGONOWFORALWAYSNIGHTANDDAYIHEARLAKEWATERLAPPINGWITHLOWSOUNDSB
YTHESHOREWHILEISTANDONTHEROADWAYORONTHEPAVEMENTSGREYIHEARITINTHEDEEPHEARTSCORE";

string original = input2; //original unchanged text with spaces, commas etc
string tempResult = result; //the new output without spaces, commas, dots etc
string fixed = ""; //string to be altered with spaces, commas etc
int originalSize = input2.size();
int i = 0, j = 0;

for(i, j; i < originalSize ;i++)
{
  if(isalnum(original[i]) || !original[i] == ' ')
{
  fixed += tempResult[j];
  j++;
}
else
{
  fixed += tempResult[j];
}
}

Answer 1

正如 cmets 中所述，提供Minimal, Complete and Verifiable example 会更容易理解您的问题，但我想我理解您想要做什么。对您的代码进行最少的修改，一种解决方案可能是这样的：

#include <iostream>
#include <string>

using namespace std;

string original = "xxxx, x xxxxx, xx x xxxxxx xxxxxxxx.";
string letters = "ThisIthinkisabetterquestion";
string desired = "This, I think, is a better question.";

int main()
{
    string fixed;
    int i, j;
    int originalSize = original.size();

    for(i=j=0; i < originalSize ;i++)
    {
        if(!isalnum(original[i]))
        {
          fixed += original[i];
        }
        else
        {
          fixed += letters[j++];
        }
    }
    cout << fixed << endl;
    cout << desired << endl;
    return 0;
}