不显示从列表中选择的选项？

Question

所以有人要求我在我的 C++ 课上制作游戏，我不久前上了 C++ 课，所以我有点生疏了。我记得你可以使用数组和列表？

游戏的重点是选择军队派系，选择军队类型，然后攻击某人。一旦我进入攻击部分，而不是从上一个菜单中检查所选派系的一堆 if 语句，我是否可以从程序的开头将派系实现到一个数组中，一旦我进入攻击阶段，运行通过数组并将用户选择的大陆与数组中的大陆进行比较，然后只保留匹配的输出？

如果有人可以发布一些代码或链接到提供此类示例的网站，将不胜感激，我想自己做，我并没有完全为我输入的东西。

#include <iostream>
using namespace std;

int main() {
//  Declare variables
int menuInput = 0, continentInput = 0, armyInput = 0, actionInput = 0;

//  Intro
cout << "WELCOME TO WAR" << endl;

//  Display main menu
do {
    cout << "1) Rules" << endl;
    cout << "2) Play Game" << endl;
    cout << "3) Quit" << endl;
    cout << "Menu choice: ";
    cin >> menuInput;


    //  if rules is selected
    if (menuInput == 1) {
        cout << endl;
        cout << "RULES: " << endl;
        cout << "1) Choose your player." << endl;
        cout << "2) Choose your army type." << endl;
        cout << "3) Choose to attack." << endl;
        cout << endl;
    }

    //  if game is selected
    else if (menuInput == 2) {
        cout << endl;
        cout << "START" << endl;

        //  first do while loop, continent choice
        do {
            cout << "1) North America" << endl;
            cout << "2) South America" << endl;
            cout << "3) Europe" << endl;
            cout << "4) Africa" << endl;
            cout << "5) Asia" << endl;
            cout << "6) Australia" << endl;
            cout << "7) Antartica" << endl;
            cout << "Choose your player from the list: ";
            cin >> continentInput;
            cout << endl;
            // invalid display if selection not in range
            if (continentInput <= 0 ||continentInput > 7) {
                cout << "INVALID" << endl;
                cout << endl;
            }
        } while (continentInput <= 0 || continentInput > 8);

        //  second do while loop, army type choice
        do {
            cout << "1) Army (Ground type forces)" << endl;
            cout << "2) Navy (Sea type forces)" << endl;
            cout << "3) Air Force (Air type forces)" << endl;
            cout << "Choose your army type from the list: ";
            cin >> armyInput;
            cout << endl;

            if (armyInput <= 0 || armyInput > 3) {
                cout << "INVALID" << endl;
            }
        } while (armyInput <= 0 || armyInput > 3);

        // third do while loop, who to attack


    }
    else if (menuInput == 3) {
        cout << endl;
        cout << "GAME OVER" << endl;
    }

    else {
        //  display invlaid input if number choice is not in given range
        cout << "INAVLID INPUT" << endl;
    }

} while (menuInput != 3);

return 0;

}

Answer 1

如果您将用户输入更改为数字，则可以引用一个填充了选项的数组。

military[x] = { "Army", "Navy" ...};
fromWhere[x] = { "North America", "South" ...};
toKill[x] = { "Whoever has oil" ... };
//get user input.
//toKill[get user input];
//kill with military[get user input];
//kill form fromWhere[get user input];
//do some attack logic 

只是提醒一下，您的问题相当模糊。你能澄清你需要什么。您似乎希望散列您的值并进行快速查找以避免字符串比较，但您不需要这样做，因为您正在获取 int 作为用户输入。