JavaScript将数组拆分为内部的多个数组[重复]

Question

如何使用 javascript 拆分以下数组？ 我在这里要做的是将这个数组拆分为这个数组内的多个数组，这些数组应该是唯一的 1、2、3、4、5 个候选配置 ID

0: {candidateConfigId: "1", value: "199128700790"}
1: {candidateConfigId: "2", value: "Yujith"}
2: {candidateConfigId: "3", value: "Male"}
3: {candidateConfigId: "4", value: "SE"}
4: {candidateConfigId: "5", value: "Colombo5"}
5: {candidateConfigId: "1", value: "199128700792"}
6: {candidateConfigId: "2", value: "Yujith2"}
7: {candidateConfigId: "3", value: "Male"}
8: {candidateConfigId: "4", value: "SE"}
9: {candidateConfigId: "5", value: "Colombo3"}
10: {candidateConfigId: "1", value: "199128700793"}
11: {candidateConfigId: "2", value: "Yujith3"}
12: {candidateConfigId: "3", value: "Male"}
13: {candidateConfigId: "4", value: "SE"}
14: {candidateConfigId: "5", value: "Colombo2"}

预期输出

[
  [
    0: {candidateConfigId: "1", value: "199128700790"}
    1: {candidateConfigId: "2", value: "Yujith"}
    2: {candidateConfigId: "3", value: "Male"}
    3: {candidateConfigId: "4", value: "SE"}
    4: {candidateConfigId: "5", value: "Colombo5"}
  ],
  [
    0: {candidateConfigId: "1", value: "199128700792"}
    1: {candidateConfigId: "2", value: "Yujith2"}
    2: {candidateConfigId: "3", value: "Male"}
    3: {candidateConfigId: "4", value: "SE"}
    4: {candidateConfigId: "5", value: "Colombo3"}
  ],
  [
    10: {candidateConfigId: "1", value: "199128700793"}
    11: {candidateConfigId: "2", value: "Yujith3"}
    12: {candidateConfigId: "3", value: "Male"}
    13: {candidateConfigId: "4", value: "SE"}
    14: {candidateConfigId: "5", value: "Colombo2"}
  ]
]
 Thanks in advance

Answer 1

您可以获取所需 id 的数组和存储同一组结果集索引的对象。

var data = [{ candidateConfigId: "1", value: "199128700790" }, { candidateConfigId: "2", value: "Yujith" }, { candidateConfigId: "3", value: "Male" }, { candidateConfigId: "4", value: "SE" }, { candidateConfigId: "5", value: "Colombo5" }, { candidateConfigId: "1", value: "199128700792" }, { candidateConfigId: "2", value: "Yujith2" }, { candidateConfigId: "3", value: "Male" }, { candidateConfigId: "4", value: "SE" }, { candidateConfigId: "5", value: "Colombo3" }, { candidateConfigId: "1", value: "199128700793" }, { candidateConfigId: "2", value: "Yujith3" }, { candidateConfigId: "3", value: "Male" }, { candidateConfigId: "4", value: "SE" }, { candidateConfigId: "5", value: "Colombo2" }],
    ids = ['1', '2', '3', '4', '5'],
    result = data
        .reduce((r, o) => {
            let index = r.indices[o.candidateConfigId]++;
            r.data[index] = r.data[index] || [];
            r.data[index].push(o);
            return r;
        }, { indices: Object.fromEntries(ids.map(k => [k, 0])), data: [] })
        .data;

console.log(result);

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Answer 2

var subject = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13];

function chunksOfSize(source, size) {
  var arr = [];
  for (var i = 0, count = source.length; i < count; i += size) {
    arr.push(arr.slice(i, i + size));
  }
  return arr;
}

console.log(chunksOfSize(subject, 4));

Answer 3

这样说：

0: {candidateConfigId: "1", value: "199128700790"}
1: {candidateConfigId: "2", value: "Yujith"}
2: {candidateConfigId: "3", value: "Male"}
3: {candidateConfigId: "4", value: "SE"}
4: {candidateConfigId: "5", value: "Colombo5"}
5: {candidateConfigId: "1", value: "199128700792"}
6: {candidateConfigId: "2", value: "Yujith2"}
7: {candidateConfigId: "3", value: "Male"}
8: {candidateConfigId: "4", value: "SE"}
9: {candidateConfigId: "5", value: "Colombo3"}
10: {candidateConfigId: "1", value: "199128700793"}
11: {candidateConfigId: "2", value: "Yujith3"}
12: {candidateConfigId: "3", value: "Male"}
13: {candidateConfigId: "4", value: "SE"}
14: {candidateConfigId: "5", value: "Colombo2"}

这个变量是：array 并且总是像发布的示例中那样排序（这是棘手的部分）。 在这种情况下，您可以使用这样的 reduce 函数：

let currentIndex = 0;
const Splitted = array.reduce((acc, cur) => {
             acc[currentIndex].push(cur);

            if (parseInt(cur.candidateConfigId) === 5) { currentIndex++; acc[currentIndex] = [] }
            return acc;
},[[]])