【发布时间】:2021-10-08 14:26:05
【问题描述】:
在 C++ 中,我希望提交一个进程,暂停、恢复和停止它。为此,我首先使用以下函数在后台运行一个 shell 进程并保存关联的 PID。我在this post 找到了这个函数(并且只删除了标准输入和输出)。
int system2(const char * command)
{
int p_stdin[2];
int p_stdout[2];
int pid;
if (pipe(p_stdin) == -1)
return -1;
if (pipe(p_stdout) == -1) {
close(p_stdin[0]);
close(p_stdin[1]);
return -1;
}
pid = fork();
if (pid < 0) {
close(p_stdin[0]);
close(p_stdin[1]);
close(p_stdout[0]);
close(p_stdout[1]);
return pid;
} else if (pid == 0) {
close(p_stdin[1]);
dup2(p_stdin[0], 0);
close(p_stdout[0]);
dup2(p_stdout[1], 1);
dup2(::open("/dev/null", O_RDONLY), 2);
/// Close all other descriptors for the safety sake.
for (int i = 3; i < 4096; ++i)
::close(i);
setsid();
execl("/bin/sh", "sh", "-c", command, NULL);
_exit(1);
}
close(p_stdin[0]);
close(p_stdout[1]);
return pid;
}
然后,我使用kill 函数来暂停、恢复和停止进程,但它没有按我预期的那样工作。这是一个例子:
int main()
{
// The process prints on file allowing me to figure out whether the process is paused / stopped, or is running
const char * command = "for i in {1..1000}; do echo $i >> /Users/remi/test/data.txt; sleep 1s;done";
// Run the command and record pid
auto pid = system2(command);
std::cout << "pid = " << pid << "\n";
// with this pid, I could ensure that `ps -p <pid>` returns the correct command
std::cout << "process should be running!\n"; // It is!
// wait
std::this_thread::sleep_for(std::chrono::seconds(10));
// pause
kill(pid, SIGTSTP);
std::cout << "process should be paused!\n"; // But it is not!
// wait
std::this_thread::sleep_for(std::chrono::seconds(10));
// resume process
kill(pid, SIGCONT);
std::cout << "process should be running!\n"; // Sure, it is as it has never been stopped
// wait
std::this_thread::sleep_for(std::chrono::seconds(10));
// Kill process
kill(pid, SIGSTOP);
std::cout << "process should be stopped!\n"; // That worked!
// wait
std::this_thread::sleep_for(std::chrono::seconds(10));
}
您能帮我弄清楚如何修复此代码,以确保进程按预期停止并恢复。
仅供参考,我使用的是 macOS,希望该解决方案适用于任何 POSIX 系统。
【问题讨论】:
-
进程可能会忽略
SIGTSTP。使用不可忽略的SIGSTOP来暂停进程。使用SIGTERM或SIGKILL杀死它。 -
行得通!我虽然无法从 SIGSTOP 恢复。谢谢。我应该删除这个问题还是我们认为这个问题可能会被其他人使用?
-
我认为这可能会有所帮助。