【发布时间】:2019-07-03 08:43:29
【问题描述】:
我正在编写一个小型 BAT 文件,它将在其中搜索“FAIL”关键字,然后搜索 PASS - 如果没有找到,则将其视为错误:
echo
set "topLevel=%cd%"
If [%1]==[] exit /B 1
If [%2]==[] exit /B 1
If [%3]==[] exit /B 1
If [%4]==[] exit /B 1
findstr /? >NUL 2>&1 || exit /B 1
set "arg1=%1"
set "arg2=%2"
set "arg3=%3"
set "arg4=%4"
set /a errno=0
if not exist %arg3% exit /B 1
if not exist %arg2%\%arg1% exit /B 1
set "logfile=%arg1:.=_%"
copy /y/v %arg2%\%arg1% %arg3%\%arg4%.%logfile%.res || exit /B 1
findstr /I /C:"FAIL" /I /C:"UNKNOWN" %arg3%\%arg4%.%logfile%.res
if %errorlevel% EQU 0 (
set /a errno=2
) ELSE (
REM MAKE SURE THAT THE SCRIPT DID NOT CRASH HENCE NEITHER PASS OR FAIL WILL BE LISTED
findstr /I /C:"PASS" %arg3%\%arg4%.%logfile%.res
if %errorlevel% NEQ 0 (
set /a errno=2
)
)
cd %topLevel%
exit /B %errno%
当我使用示例数据运行时,我得到以下输出:
..............................................
C:\agent\_work\30\s1>copy /y/v C:\output\test.log C:\agent\_work\30\s1\tttt.test_log.res || exit /B 1
1 file(s) copied.
C:\agent\_work\30\s1>findstr /I /C:"FAIL" /I /C:"UNKNOWN" C:\agent\_work\30\s1\tttt.SystemWalk_log.res
C:\agent\_work\30\s1>if 1 EQU 0 (set /a errno=2 ) ELSE (
REM MAKE SURE THAT THE SCRIPT DID NOT CRASH HENCE NEITHER PASS OR FAIL WILL BE LISTED
findstr /I /C:"PASS" C:\agent\_work\30\s1\tttt.test_log.res
if 1 NEQ 0 (set /a errno=2 )
)
PASSED
PASSED
PASSED
PASSED
PASSED
C:\agent\_work\30\s1>cd C:\agent\_work\30\s1
C:\agent\_work\30\s1>exit /B 2
C:\agent\_work\30\s1>echo %ERRORLEVEL%
2
实际上是因为它找到了“PASS”字符串而没有找到“FAIL”字符串 - 所以错误级别应该是 0 - 我该如何解决这个问题?
【问题讨论】:
-
对不起,我使用的是 Win 10
-
您发布的输出并不是运行您发布的脚本的真实反映。很明显
%1要么是test.log要么是SystemWalk.log,而不是两者,我假设实际的论点是后者。以后进行不必要的更改时请小心。期望某些邪恶的天才可以通过您系统的C:\output中的文件名来识别您的 PC、您自己、您的雇主等,这是绝对不合理的。
标签: windows batch-file cmd errorlevel