【问题标题】:How to properly use await/async with for loops in node js如何在节点 js 中正确使用等待/异步与 for 循环
【发布时间】:2020-12-02 20:02:17
【问题描述】:

我正在尝试提出一个函数,该函数将目录中的所有歌曲与文件路径、持续时间和上次访问时间一起作为列表提供。虽然循环内的日志确实打印了所需的内容,但响应是在循环完成之前发送的。

observation0:最后的日志发生在循环内的日志之前

router.get('/', function (req, res) {

    let collection = new Array();

    // glob returns an array 'results' containg the path of every subdirectory and file in the given location
    glob("D:\\Music" + "/**/*", async (err, results) => {

        // Filter out the required files and prepare them to be served in the required format by
        for (let i = 0; i < results.length; i++) {
            if (results[i].match(".mp3$") || results[i].match(".ogg$") || results[i].match(".wav$")) {

                // To get the alst accessed time of the file: stat.atime
                fs.stat(results[i], async (err, stat) => {
                    if (!err) {

                        // To get the duration if that mp3 song
                        duration(results[i], async (err, length) => {
                            if (!err) {
                                let minutes = Math.floor(length / 60)
                                let remainingSeconds = Math.floor(length) - minutes * 60

                                // The format to be served
                                let file = new Object()
                                file.key = results[i]
                                file.duration = String(minutes) + ' : ' + String(remainingSeconds)
                                file.lastListend = moment(stat.atime).fromNow()

                                collection.push(file)
                                console.log(collection) //this does log every iteration
                            }
                        })
                    }
                })
            }
        }
        console.log(collection); //logs an empty array
    })

    res.json({
        allSnongs: collection
    });
});

我无法在一定程度上理解文档,从而使我能够自己纠正代码:(

感谢您的帮助和建议

【问题讨论】:

  • 问题不在于循环与async/await 的组合,它工作得很好,问题是你传递的是普通的旧异步回调而不是使用(和awaiting ) 承诺。

标签: javascript node.js asynchronous async-await fs


【解决方案1】:

此答案不会修复您的代码,而只是为了消除任何误解:

fs.stat(path, callback); // fs.stat is always asynchronous.
                         // callback is not (normally), 
                         // but callback will run sometime in the future.

await 像 fs.stat 这样使用回调而不是承诺的函数的唯一方法是自己做出承诺。

function promiseStat( path ){
    return new Promise( ( resolve, reject ) => {
        fs.stat( path, ( err, stat ) => {
            if( err ) reject( err );
            else resolve( stat );
        };
    });
 }

现在我们可以:

const stat = await promiseStat( path );

【讨论】:

    【解决方案2】:

    有大量时间来玩弄您的代码。
    我会这样写,我做了很多改变。它有效

    srv.get('/', async function (req, res) {
    
        // glob returns an array 'results' containg the path of every subdirectory and file in the given location
        let results = await new Promise((res, rej) =>
            glob("D:\\Music" + "/**/*", (err, results) => {
                if (err != null) rej(err);
                else res(results);
            })
        );
    
        // Filter out the required files and prepare them to be served in the required format by
        results = results.filter(
            (result) =>
                /\.mp3$/.test(result) ||
                /\.ogg$/.test(result) ||
                /\.wav$/.test(result)
        );
    
        const collection = await Promise.all(
            results.map(async (result) => {
                const stat = await new Promise((res, rej) =>
                    fs.stat(result, (err, stat) => {
                        if (err != null) rej(err);
                        else res(stat);
                    })
                );
    
                const length = await new Promise((res, rej) =>
                    duration(result, (err, length) => {
                        if (err != null) rej(err);
                        else res(length);
                    })
                );
    
                const minutes = Math.floor(length / 60);
                const remainingSeconds = Math.floor(length) - minutes * 60;
    
                // The format to be served
                return {
                    key: result,
                    duration: `${minutes} : ${remainingSeconds}`,
                    lastListend: moment(stat.atime).fromNow(),
                };
            })
        );
    
        console.log(collection);
        res.json({
            allSnongs: collection,
        });
    });
    
    

    给予,

    [
      {
        key: 'D:\Music\1.mp3',
        duration: '0 : 27',
        lastListend: 'a few seconds ago'
      },
      {
        key: 'D:\Music\1.mp3',
        duration: '0 : 27',
        lastListend: 'a few seconds ago'
      },
      {
        key: 'D:\Music\1.mp3',
        duration: '0 : 52',
        lastListend: 'a few seconds ago'
      },
      {
        key: 'D:\Music\1.mp3',
        duration: '2 : 12',
        lastListend: 'a few seconds ago'
      }
    ]
    

    【讨论】:

    • 不要在回调中使用collection.push(…),而是使用return的值并使用const collection = await Promise.all(…)
    • @Bergi +1,这样更好
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