【问题标题】:How do I create a blackjack game as a simulation between two players? [closed]如何创建一个二十一点游戏作为两个玩家之间的模拟? [关闭]
【发布时间】:2016-07-20 21:00:26
【问题描述】:

我一直在努力弄清楚如何将此程序转换为两个玩家之间的程序,而不仅仅是庄家和我。它是否应该以某种方式循环,将循环的第一次迭代给玩家 1,而不是给玩家 2?我不太确定如何使它工作。

def main():
    deck = create_deck()

    num_cards = int(input('How many cards should I deal? '))

    deal_cards(deck, num_cards)

def create_deck():
    deck = {'Ace of Spades':1, '2 of Spades':2, '3 of Spades':3, 
            '4 of Spades':4, '5 of Spades':5, '6 of Spades':6, 
            '7 of Spades':7, '8 of Spades':8, '9 of Spades':9, 
            '10 of Spades':10, 'Jack of Spades':10, 
            'Queen of Spades':10, 'King of Spades': 10, 
            'Ace of Hearts':1, '2 of Hearts':2, '3 of Hearts':3, 
            '4 of Hearts':4, '5 of Hearts':5, '6 of Hearts':6, 
            '7 of Hearts':7, '8 of Hearts':8, '9 of Hearts':9, 
            '10 of Hearts':10, 'Jack of Hearts':10, 
            'Queen of Hearts':10, 'King of Hearts': 10, 'Ace of Clubs':1,
            '2 of Clubs':2, '3 of Clubs':3, '4 of Clubs':4, '5 of Clubs':5,
            '6 of Clubs':6,'7 of Clubs':7, '8 of Clubs':8, '9 of Clubs':9,
            '10 of Clubs':10, 'Jack of Clubs':10,
            'Queen of Clubs':10, 'King of Clubs': 10,
            'Ace of Diamonds':1, '2 of Diamonds':2, '3 of Diamonds':3, 
            '4 of Diamonds':4, '5 of Diamonds':5, '6 of Diamonds':6, 
            '7 of Diamonds':7, '8 of Diamonds':8, '9 of Diamonds':9, 
            '10 of Diamonds':10, 'Jack of Diamonds':10, 
            'Queen of Diamonds':10, 'King of Diamonds': 10}

    return deck

def deal_cards(deck, number):
    hand_value = 0

    if number > len(deck):
        number = len(deck)

    for count in range(number):
        card, value = deck.popitem()
        print(card)
        hand_value += value

        print('Value of this hand:', hand_value)

main()

【问题讨论】:

  • 您没有包含您询问的代码...您正在查看的这个示例的肉和土豆可能在 main() 函数中
  • 不太清楚你的意思,“我一直在努力想办法把这个程序转换成两个玩家之间的一个,而不仅仅是庄家和我。”这就是我所说的。
  • 这是个问题 - 您的具体编程问题是什么? “我不确定如何使它工作”不是一个可以回答的问题。

标签: python simulation blackjack


【解决方案1】:

我建议尝试这样的事情:

import random

deck = {'Ace of Spades':1, '2 of Spades':2, '3 of Spades':3,
        '4 of Spades':4, '5 of Spades':5, '6 of Spades':6,
        '7 of Spades':7, '8 of Spades':8, '9 of Spades':9,
        '10 of Spades':10, 'Jack of Spades':10,
        'Queen of Spades':10, 'King of Spades': 10,
        'Ace of Hearts':1, '2 of Hearts':2, '3 of Hearts':3,
        '4 of Hearts':4, '5 of Hearts':5, '6 of Hearts':6,
        '7 of Hearts':7, '8 of Hearts':8, '9 of Hearts':9,
        '10 of Hearts':10, 'Jack of Hearts':10,
        'Queen of Hearts':10, 'King of Hearts': 10, 'Ace of Clubs':1,
        '2 of Clubs':2, '3 of Clubs':3, '4 of Clubs':4, '5 of Clubs':5,
        '6 of Clubs':6,'7 of Clubs':7, '8 of Clubs':8, '9 of Clubs':9,
        '10 of Clubs':10, 'Jack of Clubs':10,
        'Queen of Clubs':10, 'King of Clubs': 10,
        'Ace of Diamonds':1, '2 of Diamonds':2, '3 of Diamonds':3,
        '4 of Diamonds':4, '5 of Diamonds':5, '6 of Diamonds':6,
        '7 of Diamonds':7, '8 of Diamonds':8, '9 of Diamonds':9,
        '10 of Diamonds':10, 'Jack of Diamonds':10,
        'Queen of Diamonds':10, 'King of Diamonds': 10}

def value(hand):
    hand_value = 0
    for i in hand:
        hand_value += deck[i]
    return hand_value


def main():
    keys = list(deck)
    random.shuffle(keys)

    player1_hand = []
    player2_hand = []
    #dealing to player 1
    while True:
        print ("Player 1's hand is ", player1_hand, "The value is ", value(player1_hand))
        response = int(input('How many cards should I deal to player1? '))
        if response == 0:
            break
        else:
            for i in range(int(response)):
                player1_hand.append(keys.pop())
    #dealing to player 2
    while True:
        print ("Player 2's hand is ", player2_hand, "The value is ", value(player2_hand))
        response = int(input('How many cards should I deal to player2? '))
        if response == 0:
            break
        else:
            for i in range(int(response)):
                player2_hand.append(keys.pop())
    print (player1_hand, value(player1_hand))
    print (player2_hand, value(player2_hand))
if __name__ == "__main__":
    main()

一些变化: 1) create_deck 函数是不必要的,因为它只是返回一个不变的变量,所以它被删除了。 2) Random.shuffle 用于套牌,因此游戏并不总是相同的。 3) 添加了“如果名称 == 主”。 这是一个简单的公式,玩家 1 获得任意数量的牌,然后玩家 2 做同样的事情。您可以循环处理 while 循环,或编写一些单独的函数来指定轮数。您还可以尝试在玩家完成发牌后打印大量换行符,以便其他玩家看不到发给他们的内容。

【讨论】:

  • 我想知道如何在我的旧代码中实现随机。出于某种原因,当我这样做时,当我测试它时它不会运行。我也没有考虑将每个玩家的值保存为单独的字典。谢谢。这使它更容易理解。
  • 我测试了代码,但由于某种原因我无法到达玩家 2,它只与玩家 1 一起运行,然后循环。
  • 如果第一个玩家请求发0张牌,它将转到第二个玩家。这就是检查'if response == 0:break'。 “响应”的输入可以更改为“你想要另一张卡(是/否)吗?”如果“是”,则玩家玩家将获得一张牌,而“否”则循环中断。
【解决方案2】:

您发布的代码仅处理用户指定数量的牌(顺便说一下,它们不是随机发的),将它们的价值相加并终止。如果你想让这个游戏连续发牌,你必须在 main 函数中添加一个循环,如下所示:

def main():
    deck = create_deck()
    while True:

        num_cards = int(input('How many cards should I deal? '))

        deal_cards(deck, num_cards)

请注意,这不会在交易之间对卡进行求和。为此,您需要在主函数中创建一个类似 p1 或 p2 的变量,并将其传递给 deal_cards。我不太确定这是否是你想要的。

【讨论】:

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