在 .cmd 中使用 Windows 命令测试是 32 位还是 64 位并运行命令

Question

我正在编写一个脚本来查找注册表值并将该值返回到 Windows 命令提示符屏幕，并将其添加到 .txt 文件中。我已经到了需要测试机器是 32 位还是 64 位的地步，这样我就知道使用哪个命令在注册表中找到我需要的值。

我正在按照我在下面写的内容寻找逻辑：

如果是 32 位则（运行此命令） 别的 （运行此命令）

我希望不必有任何文本文件或此脚本工作所需的任何其他内容。以下是我到目前为止的代码。由于注册表位置是私有的，我将位置更改为一个虚构的位置。 （注意：我确实有一个文本文件，该脚本从中读取我插入计算机和服务器的名称。到目前为止，我的代码可以工作，但是使用 2 个注册表查找命令，当它检查 32 位机器时，我显然没有得到正确的结果对于 64 位注册表位置）

@echo off

Setlocal

::sets the ldt variable to the local date and time in yyyymmdd_hhmmss
for /f "skip=1" %%c in ('wmic os get LocalDateTime') do set ldt=%%c
set ldt=%ldt:~0,8%_%ldt:~8,6%


::searches for computer names in servers.txt and then calls server sub routine. Once it goes back to the for loop it moves onto the next line in servers.txt
for /f %%c in (servers.txt) do (
set server=%%c
call:server
)
pause
goto:eof

--------------------------------------------------------------------
:server
set stamp=%date% at %time%
set DateTime=%stamp%

::Tests for a good ping, if no ping then move onto next machine
ping -n 1 -w 250 %server% > nul 
if %errorlevel% NEQ 0 (
  ECHO No Ping on %server%
  ECHO No Ping on %server% >>AuditScript_%ldt%.txt
  goto:eof
)
call:screen
call:log
goto:eof

--------------------------------------------------------------------
:screen
echo.
echo Computer name: %server%
reg query "\\%server%\HKLM\SOFTWARE\Registry Folder1\Information\" /V "Datavalue" | FIND "Datavalue"
reg query "\\%server%\HKLM\SOFTWARE\Wow6432Node\Registry Folder1\Information" /V "Datavalue" | FIND "Datavalue"
echo.
goto:eof

--------------------------------------------------------------------
:log
echo. >>AuditScript_%ldt%.txt
echo Registry value for %server% on %stamp% >>AuditScript_%ldt%.txt
reg query "\\%server%\HKLM\SOFTWARE\Registry Folder1\Information\" /V "Datavalue" | FIND "Datavalue" >>AuditScript_%ldt%.txt
reg query "\\%server%\HKLM\SOFTWARE\Wow6432Node\Registry Folder1\Information" /V "Datavalue" | FIND "Datavalue" >>AuditScript_%ldt%.txt
echo. >>AuditScript_%ldt%.txt
goto:eof

--------------------------------------------------------------------

Answer 1

:: Installed OS
Set _Bitness=64
IF %PROCESSOR_ARCHITECTURE% == x86 (
  IF NOT DEFINED PROCESSOR_ARCHITEW6432 Set _Bitness=32
  )
Echo Operating System is %_Bitness% bit

我认为这行得通

Answer 2

FOR /F "tokens=3" %%x in ('reg query "HKLM\SYSTEM\CurrentControlSet\Control\Session Manager\Environment" /V PROCESSOR_ARCHITECTURE') do set CPU=%%x
echo CPU Architecture: %CPU%
if "%CPU:~-2%"=="64" (
  echo Do This
) else (
  echo Do That
)

Answer 3

通过 cmd 你可以像这样检查%PROCESSOR_ARCHITECTURE% 变量：

echo %PROCESSOR_ARCHITECTURE% 这将根据操作系统输出x86 或x64

所以你可以使用类似的东西：

@echo off

if %PROCESSOR_ARCHITECTURE% == x86 (
goto :x86
) else (
goto :x64
)

:x86
start "foo.exe"
goto :eof

:x64
start "bar.exe"
goto :eof

Answer 4

试试这个：

setlocal EnableDelayedExpansion

for /f "delims== tokens=2" %%a in ('wmic os get osarchitecture /value') do (
  set arch=%%a
)

if "%arch%"=="32-bit" (
  rem do some
) else (
  rem do other
)

endlocal