【发布时间】:2016-11-11 16:16:42
【问题描述】:
我想总结一下data.table。看起来是这样的:
> DF
new_src action
1: cdn.adnxs.com 1
2: cdn.adnxs.com 1
3: cdn.adnxs.com 1
4: cdn.adnxs.com 3
5: s1.2mdn.net 1
6: cdn.adnxs.com 3
7: cdn.adnxs.com 3
8: cdn.adnxs.com 3
9: cdn.adnxs.com 3
10: cdn.adnxs.com 3
我想按new_src 聚合,通过action 找到最高出现次数,计算频率,打印这个action,打印总数。
我可以在ddply 中使用table 执行此操作,并在ddply 中重用变量,因此我不需要多次运行table。
我需要在data.table 中执行此操作,但我无法重复使用table 结果,我必须运行table 两次。
示例。这有效:
DF = structure(list(new_src = c("cdn.adnxs.com", "cdn.adnxs.com",
"cdn.adnxs.com", "cdn.adnxs.com", "s1.2mdn.net", "cdn.adnxs.com",
"cdn.adnxs.com", "cdn.adnxs.com", "cdn.adnxs.com", "cdn.adnxs.com"), action = c("1", "1", "1", "3", "1", "3", "3", "3", "3", "3")), .Names = c("new_src", "action"), class = c("data.table", "data.frame"), row.names = c(NA, -10L))
dt = DF[1:10,by=list(new_src),list(tb = sort(table(action),decreasing=T)[1], nm = names(sort(table(action),decreasing=T)[1]),tot = .N)]
View(dt)
ddpl = ddply(DF,.(new_src),summarize,tb = sort(table(action),decreasing=T)[1], nm = names(tb), tot = length(new_src))
View(ddpl)
这不是。
dt = DF[1:10,by=list(new_src),list(tb = sort(table(action),decreasing=T)[1], nm = names(tb),tot = .N)]
data.table 可以吗?谢谢
【问题讨论】:
标签: r data.table plyr