【发布时间】:2017-12-01 16:25:35
【问题描述】:
我有一个如下的数据框:
Date <- as.Date(c('2017-10-16',
'2017-10-16',
'2017-10-17',
'2017-10-17',
'2017-10-18',
'2017-10-18',
'2017-10-19',
'2017-10-19',
'2017-10-20',
'2017-10-20'))
Source <- as.Date(c('2017-11-29',
'2017-11-30',
'2017-11-29',
'2017-11-30',
'2017-11-29',
'2017-11-30',
'2017-11-29',
'2017-11-30',
'2017-11-29',
'2017-11-30'))
Revenue <- c(206.88,
210.88,
194.13,
200.13,
170.00,
170.00,
746.65,
736.65,
772.00,
772.00)
Cost <- c(100.88,
10.88,
85.13,
100.13,
170.00,
100.00,
46.65,
50.65,
23.00,
24.00)
df <- data.frame(Date, Source, Revenue, Cost)
数据框:
df
Date Source Revenue Cost
1 2017-10-16 2017-11-29 206.88 100.88
2 2017-10-16 2017-11-30 210.88 10.88
3 2017-10-17 2017-11-29 194.13 85.13
4 2017-10-17 2017-11-30 200.13 100.13
5 2017-10-18 2017-11-29 170.00 170.00
6 2017-10-18 2017-11-30 170.00 100.00
7 2017-10-19 2017-11-29 746.65 46.65
8 2017-10-19 2017-11-30 736.65 50.65
9 2017-10-20 2017-11-29 772.00 23.00
10 2017-10-20 2017-11-30 772.00 24.00
如何按日期计算运行差异,但对第二个之后的每一列都执行此操作?
最终结果需要如下所示:
Date Source Revenue Cost Revenue_Diff Cost_Diff .....................
1 2017-10-16 2017-11-29 206.88 100.88 NA NA .....................
2 2017-10-16 2017-11-30 210.88 10.88 4 -90 .....................
3 2017-10-17 2017-11-29 194.13 85.13 NA NA .....................
4 2017-10-17 2017-11-30 200.13 100.13 6 15 .....................
5 2017-10-18 2017-11-29 170.00 170.00 NA NA .....................
6 2017-10-18 2017-11-30 170.00 100.00 0 -70 .....................
7 2017-10-19 2017-11-29 746.65 46.65 NA NA .....................
8 2017-10-19 2017-11-30 736.65 50.65 -10 4 .....................
9 2017-10-20 2017-11-29 772.00 23.00 NA NA .....................
10 2017-10-20 2017-11-30 772.00 24.00 0 1 .....................
我当前的脚本一次只能执行 1 列,但我希望能够执行 Source 右侧的所有操作:
test<-df %>%
group_by(Date) %>%
mutate(Revenue_Diff = c(NA, diff(`Revenue`)))
任何帮助都会很棒,谢谢!
【问题讨论】: