您的循环似乎是不必要的(您没有对i 做任何事情)。相反,您可以使用summarize_at 来实现您想要的效果:
myfun <- function(db,var1, ...) {
var1 <- enquo(var1)
var2 <- quos(...)
db %>%
group_by(!!var1) %>%
summarise_at(vars(!!!var2), c(mean = mean, sd = sd))
}
如果我们用 diamonds 数据集对其进行测试:
myfun(diamonds, cut, x, z)
cut x_mean z_mean x_sd z_sd
<ord> <dbl> <dbl> <dbl> <dbl>
1 Fair 6.25 3.98 0.964 0.652
2 Good 5.84 3.64 1.06 0.655
3 Very Good 5.74 3.56 1.10 0.730
4 Premium 5.97 3.65 1.19 0.731
5 Ideal 5.51 3.40 1.06 0.658
为了使格式更接近您在原始帖子中的想法,我们可以使用一点 tidyr 魔法:
myfun <- function(db,var1, ...) {
var1 <- enquo(var1)
var2 <- quos(...)
db %>%
group_by(!!var1) %>%
summarise_at(vars(!!!var2), c(mean = mean, sd = sd)) %>%
gather(variable, value, -(!!var1)) %>%
separate(variable, c('variable', 'measure'), sep = '_') %>%
spread(measure, value) %>%
arrange(variable, !!var1)
}
cut variable mean sd
<ord> <chr> <dbl> <dbl>
1 Fair x 6.25 0.964
2 Good x 5.84 1.06
3 Very Good x 5.74 1.10
4 Premium x 5.97 1.19
5 Ideal x 5.51 1.06
6 Fair z 3.98 0.652
7 Good z 3.64 0.655
8 Very Good z 3.56 0.730
9 Premium z 3.65 0.731
10 Ideal z 3.40 0.658