【问题标题】:Change coefficient name for stargazer output更改观星器输出的系数名称
【发布时间】:2015-06-30 11:22:05
【问题描述】:

我最近收到一个关于the answer here 的问题,关于如何在使用 Stargazer 输出回归结果时更改变量名称。答案不适用于 rmslrm 函数。具体来说,系数输出正确,但标准误差消失了。这是一个可重现的示例:

library(rms)
library(stargazer)
stargazer(attitude)

# logit models
m1 <- lrm(rating ~ complaints + learning + privileges,x=TRUE, y=TRUE,data=attitude)
m2 <- lrm(rating ~ complaints + learning + privileges,x=TRUE, y=TRUE,data=attitude)
names(m1$coefficients)[names(m1$coefficients) == "privileges"] <- "past"
names(m2$coefficients)[names(m2$coefficients) == "privileges"] <- "past"

stargazer(m1,m2, type="text")

知道如何进行这项工作吗?

【问题讨论】:

    标签: r regression stargazer


    【解决方案1】:

    答案是lrm 类对象不仅存储系数,还存储方差-协方差矩阵,因此您需要执行额外的步骤:

    rownames(m1$var)[rownames(m1$var) == "privileges"] <- "past"
    rownames(m2$var)[rownames(m2$var) == "privileges"] <- "past"
    colnames(m1$var)[colnames(m1$var) == "privileges"] <- "past"
    colnames(m2$var)[colnames(m2$var) == "privileges"] <- "past"
    

    这会改变方差-协方差矩阵的行名和列名,从而产生正确的结果:

    stargazer(m1,m2, type="text")
    
    ==========================================
                      Dependent variable:     
                  ----------------------------
                             rating           
                       (1)            (2)     
    ------------------------------------------
    
    ....
    
    complaints       0.196***      0.196***   
                     (0.045)        (0.045)   
    
    learning          0.063          0.063    
                     (0.039)        (0.039)   
    
    past              -0.034        -0.034    
                     (0.035)        (0.035)   
    
    ------------------------------------------
    Observations        30            30      
    R2                0.713          0.713    
    chi2 (df = 3)   37.238***      37.238***  
    ==========================================
    Note:          *p<0.1; **p<0.05; ***p<0.01
    

    【讨论】:

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