【发布时间】:2020-01-22 14:37:17
【问题描述】:
想象一下,我有一个 CTE,它创建了一个结果集,其中包含我需要的所有信息,并且需要对结果集进行大量条件计数。有没有比一堆子查询更好的方法?
我也不能使用count() over (),因为我有时需要对值进行不同的计数,并且使用case when val=true then 1 else null end 有条件地计数并不能让我清楚地计数,更不用说它基本上与做一堆子查询。
有什么建议,还是要创建一堆子查询?
表定义
create table person (id int, name varchar2(20), age int, cityID int);
create table city (id int, name varchar2(20), stateID int);
create table state (id int, name varchar2(20));
insert into person values(1, 'Bob', 45, 1);
insert into person values(2, 'Joe', 33, 1);
insert into person values(3, 'Craig', 20, 1);
insert into person values(4, 'Alex', 45, 2);
insert into person values(5, 'Kevin', 33, 3);
insert into city values(1, 'Chicago', 1);
insert into city values(2, 'New York', 2);
insert into city values(3, 'Los Angeles', 3);
insert into state values(1, 'Illinois');
insert into state values(2, 'New York');
insert into state values(3, 'California');
SQL 查询示例
with cte as (
select p.name pName
, p.age pAge
, c.name cName
, s.name sName
from person p
inner join city c
on p.cityID = c.ID
inner join state s
on c.stateID = s.ID
)
select distinct
(select count(*) from cte) totalRows
, (select count(*) from cte where pAge = 45) total45YO
, (select count(*) from cte where cName like 'Chicago') totalChicago
, (select count(distinct cName) from cte) totalCities
from cte
我希望的示例输出
TOTALROWS TOTAL45YO TOTALCHICAGO TOTALCITIES
------------------------------------------------------
5 2 3 3
【问题讨论】:
-
select ... , sum(case when cName = 'Chicago' then 1 else 0 end) as totalChicago, ...
标签: sql oracle count oracle12c