Datepart 结果格式为时间

Question

我有这个问题

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    (SELECT DATEPART(HOUR, OutTime)) - (SELECT DATEPART(HOUR, InTime)) as lebih 
FROM 
    DinasAuditHeader a 
INNER JOIN
    DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
INNER JOIN
    Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
INNER JOIN
    employee d on c.Nip = d.Nip 
WHERE
    b.Nip = '1502427' 
    AND c.AttendanceCode = 'P3' 
    AND a.KodeAuditHeader = 'AD0000001'

从查询中我得到这个结果

Nip      FullName   KodeDetailDinas KodeAuditHeader nip    AttendanceDate   claim_status    InTime                      OutTime         lebih
1502427 FERNANDO ALIM      1          AD0000001   1502427   2016-08-28           0      2016-08-28 08:55:00.000 2016-08-28 21:03:00.000 13
1502427 FERNANDO ALIM      3          AD0000001   1502427   2016-08-30           0      2016-08-30 08:55:00.000 2016-08-30 18:03:00.000 10
1502427 FERNANDO ALIM      2          AD0000001   1502427   2016-08-29           0      2016-08-29 08:55:00.000 2016-08-29 19:03:00.000 11
1502427 FERNANDO ALIM      4          AD0000001   1502427   2016-08-31           0      2016-08-31 08:50:00.000 2016-08-31 20:03:00.000 12

从我的查询和结果中可以看出。我有一个名为lebih 的专栏。 lebih 是 InTime 和 OutTime 之间的结果范围。

我有两个问题。

1. 从我上面的查询中我只能得到hour。那么如何转换成这种格式hh:mm

2. 如何查看它们之间的范围（OutTime - InTime）然后用- 08:00 减去？

Answer 1

你可以试试SELECT CONVERT(VARCHAR(5),(OutTime - InTime),108) AS lebih

以下 Sql 查询应该适用于您的情况：

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    CONVERT(VARCHAR(5),(OutTime - InTime),108) AS lebih
FROM 
    DinasAuditHeader a 
INNER JOIN
    DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
INNER JOIN
    Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
INNER JOIN
    employee d on c.Nip = d.Nip 
WHERE
    b.Nip = '1502427' 
    AND c.AttendanceCode = 'P3' 
    AND a.KodeAuditHeader = 'AD0000001'

更新：

要从 lebih 中减去 8 小时，您可以使用

CONVERT(VARCHAR(5), DATEADD(HOUR, -8, OutTime - InTime), 108) AS lebih

Answer 2

对于第 1 个问题。你可以使用 @Unnikrishnan R 答案。然后对于第二个尝试下面的查询。

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,OutTime),'2011-01-01 00:00') AS TIME),5) lebih ,
    LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,DATEADD(HOUR, -8, OutTime)),'2011-01-01 00:00') AS TIME),5) 
FROM DinasAuditHeader a 
 INNER JOIN DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
 INNER JOIN Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
 INNER JOIN employee d on c.Nip = d.Nip 
WHERE b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'
order by KodeDetailDinas asc

Answer 3

使用脚本获取 'HH:MM' 中的时差。

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,OutTime),'2011-01-01 00:00') AS TIME),5) as lebih
FROM DinasAuditHeader a 
 INNER JOIN DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
 INNER JOIN Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
 INNER JOIN employee d on c.Nip = d.Nip 
WHERE b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

查看示例查询的结果。 Time difference in HH:MM

Answer 4

将VARCHAR 附加到':00' 的简单转换怎么样？

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast((SELECT DATEPART(HOUR, OutTime)) - (SELECT DATEPART(HOUR, InTime)) AS VARCHAR(2)) + ':00' as lebih 
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

如果你想精确到MINUTE，最好使用DATEDIFF

select 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast(DATEDIFF(MINUTE, InTime, OutTime) / 60) as varchar(2)) + ':' 
    + cast(DATEDIFF(MINUTE, InTime, OutTime) % 60) as varchar(2))
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

如果您想将时间结果再分 8 小时，您可以先将 OutTime 8 小时向后推。

select 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast(DATEDIFF(MINUTE, InTime, DATEADD(HOUR, -8, OutTime)) / 60) as varchar(2)) + ':' 
    + cast(DATEDIFF(MINUTE, InTime, DATEADD(HOUR, -8, OutTime)) % 60) as varchar(2))
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'