使用 sql 的分层记录

Question

我有一张这样的桌子

**id    exType               exId   depType              depId**    
  1     Ceo                  1      Board Of Director      1    
  2     Board Of Director    1      Manager                4    
  3     Board Of Director    1      Manager                5    
  4     Manager              4      TeamLead               1    
  5     Manager              5      TeamLead               2    
  6     TeamLead             1      Member                 7    
  7     TeamLead             1      Member                 8    
  8     TeamLead             1      Member                 9    
  9     TeamLead             1      Member                 10   
  10    TeamLead             2      Member                19

当我输入 exType 为 Manager 和 exId 为 4 时，我想要所有成员的输入

                                    Member                 7    
                                    Member                 8    
                                    Member                 9    
                                    Member                 10   

或者当我将输入作为 exType 作为 teamlead 并将 exId 作为 1 我想要时，我想要所有成员的输入

                                    Member                 7    
                                    Member                 8    
                                    Member                 9    
                                    Member                 10   

或者当我输入 exType 作为 CEO 和 exId 作为 1 我想要输入时，我想要所有成员的输入

                                    Member                 7    
                                    Member                 8    
                                    Member                 9    
                                    Member                 10   

Answer 1

您可以使用递归查询来展示给定节点的所有依赖项：

with recursive cte as (
    select depType, depId 
    from mytable 
    where exType = 'Manager' and exId = 4
    union all
    select t.depType, t.depId
    from cte c
    inner join mytable t on t.exId = c.depId and t.exType = c.depType
)
select * from cte