【问题标题】:Updating a table using Case statements in SQL在 SQL 中使用 Case 语句更新表
【发布时间】:2019-03-08 18:57:54
【问题描述】:

我正在尝试将 0、1 或 null 添加到特定类别中的列,其中 relativepersonidperson 具有 diagdatepersonservicedate。这是我的表:

 DROP TABLE ICDCodes_w;
 GO
 CREATE TABLE ICDCodes_w
(
    AnxietyDisorder VARCHAR(6),
    DepressiveDisorder VARCHAR(6),
    PTSD VARCHAR(6)
);

INSERT INTO ICDCodes_w
(
    AnxietyDisorder,
    DepressiveDisorder,
    PTSD
)
VALUES
('293.84', '296.2', '309.81'),
('300', '296.21', 'F43.1'),
('305.42', 'F11.28', 'F31.76'),
('305.81', 'F43.8', 'F31.78'),
('F40.00', 'F43.10', '305.52');
GO
DROP TABLE DiagHX_w;
GO
CREATE TABLE DiagHX_w
(
    ArchiveID VARCHAR(10),
    RelativePersonID VARCHAR(10),
    ICDCode VARCHAR(6), 
    DiagDate DATE 
);

INSERT INTO DiagHX_w
(
    ArchiveID,
    RelativePersonID,
    ICDCode, 
    DiagDate
)
VALUES
('1275741', '754241', '293.84', '1989-01-03'),
('2154872', '754241', '293.84', '1995-04-07'),
('4587215', '754241', '998.4', '1999-12-07'),
('4588775', '711121', 'F11.28', '2001-02-07'),
('3545455', '711121', NULL, NULL),
('9876352', '323668', '400.02', '1988-04-09'),
('3211514', '112101', 'F31.78', '2005-09-09'),
('3254548', '686967', 'F40.00', '1999-12-31'),
('4411144', '686967', '305.52', '2000-01-01'),
('6548785', '99999999','F40.00', '2000-02-03');
GO
DROP TABLE PatientFlags_w;
GO
CREATE TABLE PatientFlags_w
(
    PersonID VARCHAR(10),
    RelativePersonID VARCHAR(10),
    AnxietyDisorder VARCHAR(2),
    DepressiveDisorder VARCHAR(2),
    PTSD VARCHAR(2),
);

INSERT INTO PatientFlags_w
(
    PersonID,
    RelativePersonID
)
VALUES
('99999999', '754241'),
('88888888', '754241'),
('77777777', '754241'),
('66666666', '711121'),
('55555555', '711121'),
('44444444', '323668'),
('33333333', '112101'),
('22222222', '686967'),
('11111111', '686967'),
('32151111', '887878'),
('78746954', '771125'),
('54621333', '333114'),
('55648888', '333114');
GO
DROP TABLE Person_w;
GO
CREATE TABLE Person_w
(
    PersonID VARCHAR(10),
    ServiceDate date
);

INSERT INTO Person_w
(
    PersonID,
    ServiceDate
)
VALUES
('99999999', '2000-12-31'),
('88888888', '2000-11-01'),
('69876541', '2000-09-04'),
('66666666', '2000-01-15'),
('55555555', '2000-07-22'),
('44444444', '2000-07-20'),
('65498711', '2000-11-17'),
('22222222', '2000-09-02'),
('11111111', '2000-02-04'),
('32151111', '2000-02-17'),
('78746954', '2000-03-29'),
('54621333', '2000-08-22'),
('55648888', '2000-10-20');

这是我的更新声明:

UPDATE a
SET AnxietyDisorder = CASE
                      WHEN ICDCode IN
                           (
                               SELECT AnxietyDisorder FROM 
                               Project..ICDCodes_w
                           ) THEN
                          1
                      ELSE
                          0
                  END,
DepressiveDisorder = CASE
                         WHEN ICDCode IN
                              (
                                  SELECT DepressiveDisorder FROM 
                                  Project..ICDCodes_w
                              ) THEN
                             1
                         ELSE
                             0
                     END,
PTSD = CASE
           WHEN ICDCode IN
                (
                    SELECT PTSD FROM Project..ICDCodes_w
                ) THEN
               1
           ELSE
               0
       END
FROM PatientFlags_w a
JOIN DiagHX_w b
    ON a.relativepersonid = b.RelativePersonID
JOIN Person_w p 
ON a.personid = p.PersonID
WHERE diagdate <= p.servicedate; 

这适用于某些值,但有些值不会更新。我知道问题出在我的案例陈述上,可能是加入问题。有什么更好的方法来写这个?这是我用来检查的示例查询。 PTSD 列应该有一个 1。

SELECT * FROM project..patientflags_w a 
JOIN project..diaghx_w b 
ON a.relativepersonid = b.RelativePersonID
JOIN project..person_w p 
ON a.personid = p.personid 
WHERE b.icdcode IN (SELECT PTSD FROM Project..ICDCodes_w) 
AND b.diagdate <= p.servicedate 

前几天我确实问过这个问题,但是我的示例表都搞砸了,所以我已经验证了它们这次可以正常工作。

【问题讨论】:

  • "这适用于某些值,但有些值不会更新" 好的,它适用于哪些,哪些不适用?当某些内容没有更新时,您希望更新什么以及更新到什么?
  • 欢迎来到 SO。您的查询,至少是案例陈述,似乎很好。如果存在未更新行的问题,则与连接或位置有关。我注意到 diagdate 上有一些空值;也许你想要 isnull(diagdate,'19000101') 代替?

标签: sql sql-server sql-server-2012 ssms


【解决方案1】:

乍一看,您查询的问题在于您多次更新目标 (PatientFlags_w):每个标志一次。在某些情况下,您似乎最终得到了正确的结果,但这只是运气。

很难判断您是希望旗表中每人一排,还是每个旗一排。

您能否查看这些查询并让我们知道它们是否接近您想要的结果:

-- If you want one row per Person:
select  RelativePersonID, 
        [AnxietyDisorder] = max(case when c.AnxietyDisorder is not null then 1 else 0 end),
        [DepressiveDisorder] = max(case when c.DepressiveDisorder is not null then 1 else 0 end),
        [PTSD] = max(case when c.PTSD is not null then 1 else 0 end)
from    DiagHX_w d
left 
join    ICDCodes_w c on d.ICDCode in (c.AnxietyDisorder, c.DepressiveDisorder, c.PTSD)
group
by      RelativePersonID;


-- If you want one row per Flag:
select  RelativePersonID, 
        d.ICDCode,
        [AnxietyDisorder] = case when c.AnxietyDisorder is not null then 1 else 0 end,
        [DepressiveDisorder] = case when c.DepressiveDisorder is not null then 1 else 0 end,
        [PTSD] = case when c.PTSD is not null then 1 else 0 end
from    DiagHX_w d
left 
join    ICDCodes_w c on d.ICDCode in (c.AnxietyDisorder, c.DepressiveDisorder, c.PTSD);

如果诊断彼此不相关(我假设因为它们在同一个表中),您可能需要这个:

select  RelativePersonID, 
        [AnxietyDisorder] = max(case when c.AnxietyDisorder = d.ICDCode then 1 else 0 end),
        [DepressiveDisorder] = max(case when c.DepressiveDisorder = d.ICDCode then 1 else 0 end),
        [PTSD] = max(case when c.PTSD = d.ICDCode then 1 else 0 end)
from    DiagHX_w d
left 
join    ICDCodes_w c on d.ICDCode in (c.AnxietyDisorder, c.DepressiveDisorder, c.PTSD)
group
by      RelativePersonID;

【讨论】:

  • 嗨,谢谢。如果 relativepersonid 曾经诊断过,我只希望一个标志为“1”,所以我只希望每个标志一行。第一个查询更接近我想要的,但是当我运行它时,看起来我仍然得到误报,反之亦然。
  • 第一个查询是每一行。帮助我将第一个查询中的误报归零。
  • 对不起,你是对的。我只想要每人一排。因此,如果此人的所有三个诊断都标记为“1”,我只想要一行。
  • SELECT a.relativepersonid, a.anxietydisorder, a.depressivedisorder, a.ptsd, b.icdcode FROM Project..PatientFlags_w 加入项目..DiagHX_w b ON a.RelativePersonID = b.RelativePersonID 加入项目..Person_w p ON a.PersonID = p.PersonID 加入项目..ICDCodes_w i ON b.ICDCode = i.PTSD; --only relativepersonid = 686967 应该有 PTSD = 1
  • 我添加了第三个查询,可能会让我们更接近。我曾假设 ICD 代码彼此相关
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