PatIndex Pattern /Regex：如何匹配点后跟空格

Question

Q1-PatIndex 模式正则表达式：如何匹配点后跟空格？ Q2 -PatIndex Pattern Regex：如何匹配一个点后跟两个空格？

我想把它放在这里只得到目标内容

 Declare @Temp Table(Data VarChar(1000))

Insert Into @Temp Values('Lalallaa GOAL: This is the truthmeow. Meow.  ')
Insert Into @Temp Values('Lalallaa GOAL: This is the truth. Meowrwr. ')
Insert Into @Temp Values('lALALLA GOAL: This is the truth. Meowrwr.  NOTINCLUDED: WAWAW')


Select Left(
             SubString(Data,PATINDEX ('%GOAL%',Data), 8000) ,
             PatIndex('regex here', SubString(Data, PatIndex('%[GOAL]%', Data), 8000))-1)
From   @Temp

预期输出

GOAL: This is the truthmeow. 
GOAL: This is the truth.
GOAL: This is the truth. 

我在真实数据库上使用了 Shnugos 答案，但遇到了错误：Illegal name character

我检查了数据类型，是ntext

Answer 1

这个呢：

简短的解释：用 xml-tags 替换 . 会将该字符串“拆分”成与您的字符串一样多的“部分”。 XML-value 方法将获取第一项的值，即字符串直到第一个 .

Declare @Temp Table(Data VarChar(1000))

Insert Into @Temp Values('Lalallaa GOAL: This is the truthmeow. Meow.  ')
Insert Into @Temp Values('Lalallaa GOAL: This is the truth. Meowrwr. ')
Insert Into @Temp Values('lALALLA GOAL: This is the truth. Meowrwr. NOTINCLUDED: WAWAW')


Select CAST('<x>' + REPLACE(SubString(Data,PATINDEX ('%GOAL%',Data), 8000),'. ','</x><x>') + '</x>' AS XML).value('x[1]','varchar(max)')
From   @Temp    

Answer 2

您也可以尝试使用 LIKE 语句。

columnname LIKE '.  %'

编辑：

试试这个：

Select SUBSTRING(data, LEN(LEFT(data, CHARINDEX ('GOAL:', data))) , LEN(data) - LEN(LEFT(data, CHARINDEX ('GOAL:', data))) - LEN(RIGHT(data, LEN(data) - CHARINDEX ('.', data))) - 1)
From   @Temp