使用 SQL 的每周计划

Question

我需要为学生制定每周计划。

• 行是 12 小时 (08:00-20:00)，
• 列为 6 天（周一至周六）。
• 学生在周一 9-11 和周二 11-14 之间有课程。
• 其他将显示为空。

我可以只用 SQL 创建一个这样的查询（矩阵）吗？

我目前的查询是这样的：

SELECT courseName, courseDay, courseStartHour, coursEndHour 
FROM courses WHERE studentId = 1

这就是我想要的：

我在 Pivot 中做到了这一点：

同一小时可以包括多个课程。 （最多 2 个）

注意：我们有 Oracle 11g。

样本（简化）数据：

CREATE TABLE StudentCourses ( courseCode varchar2(8) NOT NULL,  courseName varchar2(64) NOT NULL,  day number(10),  startHour number(10),  endHour number(10));

INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 352','Advertising Copywriting','1','9','11' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 352','Advertising Copywriting','1','11','13' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 332','Positioning Strategy in Advertising','2','9','12' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'COMM 324','Persuasion and Perception','2','14', '17' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 312','Corporate Communications Practicum','3','14','17' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 302','Strategic Media Planning','4','9','11' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 302','Strategic Media Planning','4','11','13' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 412','Case Studies in Advertising','4','13','15' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 411','Advertising Photography','4','14','16' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 412','Case Studies in Advertising','4','15','17' );
INSERT INTO StudentCourses (courseCode, courseName, day, startHour, endHour ) VALUES ( 'ADV 411','Advertising Photography','4','16','18' );

Answer 1

这是一个更简单的。

WITH TEMP AS(SELECT LEVEL+7 AS HR  FROM DUAL CONNECT BY LEVEL <= 12)
SELECT TEMP.HR AS "HOUR",
       CASE WHEN TEMP.HR BETWEEN 9 AND 11 THEN 'X' ELSE NULL END AS MON,
       CASE WHEN TEMP.HR BETWEEN 11 AND 14 THEN 'X' ELSE NULL END AS TUE,
       NULL AS WED,
       NULL AS THU,
       NULL AS FRI,
       NULL AS SAT,
       NULL AS SUN
       FROM DUAL, TEMP

Answer 2

这是你需要的吗？

with tab as (
select 8 as "hour", null as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday from dual union all
select 9 as "hour", 'x' as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 10 as "hour", 'x' as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 11 as "hour", 'x' as monday, 'x' as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 12 as "hour", null as monday, 'x' as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 13 as "hour", null as monday, 'x' as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 14 as "hour", null as monday, 'x' as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 15 as "hour", null as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 16 as "hour", null as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 17 as "hour", null as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual union all
select 18 as "hour", null as monday, null as tuesday, null as wednesday, null as thursday, null as friday, null as saturday  from dual 
)
select * from tab