【发布时间】:2014-07-11 11:09:42
【问题描述】:
请看看这个fiddle
是否可以将这四个不同的查询组合成一个语句?
SELECT DISTINCT(name) from `product` order by name;
SELECT DISTINCT (category) from `product` order by category;
SELECT DISTINCT (price) from `product` order by price;
SELECT DISTINCT (year) from `product` order by year;
我想从每列中获取不同的行并以 JSON 格式返回选择框选项的结果,但我不知道如何在不使用四个独立的选择语句的情况下返回如下结果:
NAME
A
C
D
E
G
CATEGORY
Brainteaser
Doll
Outdoor
PRICE
20
22
25
30
34
YEAR
2008
2009
2010
表:
创建表产品
(ID int, name varchar(1), category varchar(11), price int,yearint)
;
INSERT INTO product
(`ID`, `name`, `category`, `price`,`year`)
VALUES
(1, 'A', 'Outdoor', 25,2010),
(2, 'A', 'Doll', 34,2009),
(3, 'C', 'Doll', 25,2008),
(4, 'D', 'Outdoor', 20,2010),
(5, 'E', 'Brainteaser', 22,2010),
(6, 'E', 'Brainteaser', 22,2009),
(7, 'G', 'Brainteaser', 30,2009),
(8, 'G', 'Brainteaser', 30,2009)
;
【问题讨论】:
标签: mysql sql group-by distinct