选择字段与多个预定义值相关联的行[重复]

Question

我很难为这个问题选择一个标题。我不确定它是否准确地描述了我想要的东西，所以如果你能帮助改进标题而不是投反对票，我将不胜感激。 :)

我有以下（示例）表格：

USERS:
+----------+
|    id    |
+----------+
|     1    |
------------
|     3    |
------------
|     4    |
+----------+
URLS:
+----------+----------+
|    id    |    url   |
+----------+----------+
|     1    |   a.com  |
-----------------------
|     1    |   b.com  |
-----------------------
|     1    |   d.com  |
-----------------------
|     2    |   a.com  |
-----------------------
|     2    |   e.com  |
-----------------------
|     3    |   a.com  |
-----------------------
|     3    |   e.com  |
-----------------------
|     3    |   f.com  |
-----------------------
|     3    |   g.com  |
-----------------------
|     4    |   a.com  |
-----------------------
|     4    |   e.com  |
+----------+----------+

我想从URLS 中选择与USERS 中至少两个ID 相对应的所有URL。因此，例如，使用这些示例表进行此类查询的结果：

+----------+
|    url   |
+----------+
|   a.com  | <- associated with ids: 1, 3, 4
------------
|   e.com  | <- associated with ids: 3, 4
+----------+

如您所见，例如，b.com 与 1 相关联，后者位于 USERS 表中。但是，因为它与 USERS 中的任何其他 id 都没有关联，所以它不在结果中。我怎样才能做到这一点？

Answer 1

如果最小值不等于最大值，您将有多个与url 关联的 id，我们可以通过执行inner join 排除不在USERS 表中的ids，所以也许像这样的

select url
from URLS as a
inner join USERS as b
on a.id=b.id
group by url
having max(b.id)<>min(b.id)

Answer 2

你可以使用EXISTS()作为

SELECT Url
FROM Urls T
WHERE EXISTS(
              SELECT 1
              FROM Urls
              WHERE ID != T.ID
                    AND
                    Url = T.Url
            )
GROUP BY Url;

或者

SELECT T1.Url
FROM Urls T1 JOIN Urls T2
ON T1.ID != T2.ID
AND T1.Url = T2.Url
GROUP BY T1.Url;

---

更新：

因为你需要加入Users table

SELECT T1.Url
FROM Urls T1 INNER JOIN Users T2
ON T1.ID = T2.ID
WHERE EXISTS(
              SELECT 1
              FROM Urls
              WHERE ID != T1.ID
                    AND
                    Url = T1.Url
            )
GROUP BY T1.Url;

SELECT T1.Url
FROM Urls T1 INNER JOIN Urls T2
ON T1.ID != T2.ID
AND T1.Url = T2.Url
INNER JOIN Users U ON T1.ID = U.ID
GROUP BY T1.Url;

Demo

Answer 3

如果您想在同一列中查看所有关联的 Id，可以使用 STUFF() 。这是您的示例：

--DROP TABLE Users;
CREATE TABLE Users
(
    id  INT
);


--DROP TABLE Urls;
CREATE TABLE Urls
(
    id  INT
    ,Url    VARCHAR(100)
);

INSERT INTO Users VALUES(1),(2),(3),(4)
INSERT INTO URLs  VALUES
 (1,'a.com')
,(1,'b.com')
,(1,'d.com')
,(2,'a.com')
,(2,'e.com')
,(3,'a.com')
,(3,'e.com')
,(3,'f.com')
,(3,'g.com')
,(4,'a.com')
,(4,'e.com')

SELECT *,
        STUFF((SELECT distinct ',' + CAST(ID AS VARCHAR)
                    from URLs U2
                    WHERE U1.Url=U2.Url
                    AND EXISTS (SELECT 1 FROM Users US WHERE U2.id=US.id)
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

FROM 
    (SELECT DISTINCT Url FROM Urls) U1