SQL查询如何使用两个日期变量？ 'date' 和 regexp_replace('date', '-', ''),1,8)

Question

SQL查询是python文件的部分代码，tt1的val和tt2的val在单个文件中都可以正常工作，现在我想计算tt1.val/tt2.val，我必须输入参数code， start_date 和 end_date，

the date from table_name_a is '20191107'

the date from table_name_b is '2019-11-07 00:00:00'

这就是我在table_name_b 中使用substr(regexp_replace(date,'-',''),1,8) 的原因，我将错误的SQL 查询粘贴如下，我可以使用case when 或if else 来使用两个不同的日期变量吗？非常感谢您的任何建议。

SELECT code, tt1.val/tt2.val
FROM (

    (
    SELECT code,
        CAST (exp(sum(ln(val+1))) -1 AS decimal(20,16)) val
    FROM (
        SELECT code, val
        from table_name_a
        WHERE code IN ('%(code)s')
        AND date BETWEEN '%(start_date)s' AND '%(end_date)s')
    GROUP BY code
    ) AS tt1
    (
    SELECT code,
        CAST (exp(sum(ln(val+1))) -1 AS decimal(20,16)) val
    FROM (
        SELECT code, val
        from table_name_b
        WHERE code IN ('%(code)s')
        AND substr(regexp_replace(date,'-',''),1,8) BETWEEN '%(start_date)s' AND '%(end_date)s' AS t1
    GROUP BY code
    ) AS tt1
) AS tt3

Answer 1

我认为您只需 JOIN 您的查询：

SELECT tt1.code, tt1.val/tt2.val
FROM (SELECT code
           , CAST (exp(sum(ln(val+1))) -1 AS decimal(20,16)) val
        FROM table_name_a
       WHERE code IN ('%(code)s')
         AND date BETWEEN '%(start_date)s' AND '%(end_date)s'
       GROUP BY code) tt1
JOIN (SELECT code
           , CAST (exp(sum(ln(val+1))) -1 AS decimal(20,16)) val
        FROM table_name_b
       WHERE code IN ('%(code)s')
         AND substr(regexp_replace(date,'-',''),1,8) BETWEEN '%(start_date)s' AND '%(end_date)s'
       GROUP BY code) tt2
  ON tt2.code = tt1.code

还稍微简化了您的查询。