【发布时间】:2012-02-21 01:22:04
【问题描述】:
我有一个触发器,我想从存储过程中启动它。我正在使用 ms 访问,当我从 ms 访问运行触发器时,它给了我一个错误消息 (ODBC)。我想我无法使用 ms 访问创建触发器。这是我的触发器:
IF EXISTS
(SELECT name
FROM sys.objects
WHERE name = 'UpdateComments' AND type = 'TR')
DROP TRIGGER tblEmailHdr_abenit01.UpdateComments;
GO
CREATE TRIGGER UpdateComments
ON tblEmailHdr_abenit01
AFTER Update
AS
IF ( UPDATE (Comments) ) BEGIN Update ttblEmailHdr_abenit01
Set UpdateComm = GetDate()
END;
GO
这就是我尝试从存储过程创建触发器的方式,但是当我尝试创建存储过程时收到以下错误消息:
存储过程:
CREATE PROCEDURE dbo.SP_AS_tblEmailHdr_Trig (@UserID as varchar(10))
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
--SET NOCOUNT ON;
-- Insert statements for procedure here
Declare @UserTable Varchar(50)
Declare @UserTable2 Varchar(50)
Set @UserTable = 'tblEmailHdr_' + @UserID ;
Set @UserTable2 = 'tblEmailHdr_' + @UserID + '.UpdateComments' ;
IF EXISTS
(SELECT name
FROM sys.objects
WHERE name = 'UpdateComments' AND type = 'TR') DROP TRIGGER @UserTable2
GO
CREATE TRIGGER UpdateComments
ON @UserTable
AFTER UPDATE
AS
IF ( UPDATE (Comments) )
BEGIN
--RAISERROR (50009, 16, 10)
Update @UserTable
Set UpdatedComm = GetDate()
END
GO
END
GO
我得到的错误信息:
Msg 102, Level 15, State 1, Procedure SP_AS_tblEmailHdr_Trig, Line 23
Incorrect syntax near '@UserTable2'.
Msg 102, Level 15, State 1, Procedure UpdateComments, Line 2
Incorrect syntax near '@UserTable'.
Msg 1087, Level 15, State 2, Procedure UpdateComments, Line 8
Must declare the table variable "@UserTable".
Msg 102, Level 15, State 1, Line 2
Incorrect syntax near 'END'.
【问题讨论】:
-
从sp里面移除GO
-
@Vikram
GO可能会阻止创建过程,但它仍然不会导致触发器被执行,因为 OP 似乎想要。 -
@Yuck:你是对的。触发器会自动执行..但我认为他正在尝试创建一个。
-
我认为您的问题表述有误,或者误解了触发器的功能。
标签: sql ms-access stored-procedures triggers