PL/SQL 输出问题

【问题标题】：Issue with PL/SQL OutputPL/SQL 输出问题
【发布时间】：2020-06-10 19:07:42
【问题描述】：

我在 Oracle SQL Developer 中创建了这个过程。

CREATE OR REPLACE PROCEDURE CUST_NAME_LIMIT(
I_CUSTOMER_NUM IN CUSTOMER.CUSTOMER_NUM%TYPE,
I_CUSTOMER_NAME OUT CUSTOMER.CUSTOMER_NAME%TYPE,
I_CREDIT_LIMIT OUT CUSTOMER.CREDIT_LIMIT%TYPE)
AS
BEGIN
SELECT CUSTOMER_NAME, CREDIT_LIMIT
INTO
I_CUSTOMER_NAME, I_CREDIT_LIMIT
FROM
CUSTOMER
WHERE
CUSTOMER_NAME = I_CUSTOMER_NAME;
DBMS_OUTPUT.PUT_LINE(I_CUSTOMER_NAME);
DBMS_OUTPUT.PUT_LINE(I_CREDIT_LIMIT);
END;

当我尝试在下面显示输出时出现错误

BEGIN
CUST_NAME_LIMIT('126');
END;

它应该输出玩具丰富 7500

【问题讨论】：

一个错误？问题在于输出，而不是过程逻辑？顺便说一句，customer_name 是否被定义为唯一的？ idownvotedbecau.se/noexceptiondetails

标签： sql oracle stored-procedures

【解决方案1】：

仅当您告诉我们您遇到了哪个错误，而不是让我们猜测。但是，嘿，这样更有趣！

当您声明一个接受一个IN 和两个OUT 参数的过程时：

create or replace procedure cust_name_limit(
  i_customer_num in customer.customer_num%type,
  i_customer_name out customer.customer_name%type,
  i_credit_limit out customer.credit_limit%type)
as
begin
  select customer_name, credit_limit
  into i_customer_name, i_credit_limit
  from customer
  where customer_name = i_customer_name;
end;

调用它时也必须这样做：

declare
  l_custname customer.customer_name%type;
  l_credlim  customer.credit_limit%type;
begin
  CUST_NAME_LIMIT('126', l_custname, l_credlim);

  dbms_output.put_line(l_custname ||' - '|| l_credlim);
end;
/

在过程中显示结果没有多大意义；一旦它返回值就这样做。

【讨论】：