【发布时间】:2015-02-02 06:56:26
【问题描述】:
我最近有一个 SQL 任务的面试,这需要使用游标,但必须为 doesn't have 游标的 SQLite 编写代码。那么,我该如何解决呢?任务如下:
Exists a table which has two columns: "b" - the beginning and "e" - the end.
Each row of this table represents 1-dimentional line - column "b"
contains coordinate of the beginning, column "e" - coordinate of
the end. e.g.:
b | e
-------
1 | 5
2 | 4
3 | 7
-------
Column "e" always greater than "b" in each row. It is required to calculate
length of covered surface on coordinate axis. For this example answer
is 6 = ((5 - 1) + (7 - 5)).
这是我的游标解决方案:
DECLARE @temp_table TABLE(b int, e int);
DECLARE [cursor] CURSOR FOR SELECT b, e FROM [table]
DECLARE @b INT
DECLARE @e INT
OPEN [cursor]
FETCH NEXT FROM [cursor] INTO @b, @e
WHILE @@FETCH_STATUS = 0
BEGIN
IF (EXISTS(SELECT * FROM @temp_table))
FETCH NEXT FROM [cursor] INTO @b, @e
IF (EXISTS(SELECT * FROM @temp_table WHERE b <= @b AND e >= @e))
CONTINUE;
IF (EXISTS(SELECT * FROM @temp_table WHERE e < @b OR b > @e)
OR NOT EXISTS(SELECT * FROM @temp_table))
BEGIN
INSERT INTO @temp_table VALUES(@b, @e)
CONTINUE
END
IF (EXISTS(SELECT * FROM @temp_table WHERE b <= @b AND e <= @e))
BEGIN
UPDATE @temp_table SET e = @e WHERE b <= @b AND e <= @e
CONTINUE;
END
IF (EXISTS(SELECT * FROM @temp_table WHERE b >= @b AND e >= @e))
BEGIN
UPDATE @temp_table SET b = @b WHERE b >= @b AND e >= @e
CONTINUE;
END
END
CLOSE [cursor]
DEALLOCATE [cursor]
SELECT SUM(e - b) FROM @temp_table
如何为 SQLite 编写相同的代码?我问了我的朋友,没有人知道。 我多次尝试解决这个任务,但都没有成功。 一想到这个悬而未决的问题,我就心烦意乱。请帮帮我! 任何帮助表示赞赏。
【问题讨论】:
-
你从哪里得到
+ (7 -5)? -
我们必须计算覆盖面。例如,从 3 到 5 的表面被第一行和最后一行覆盖 2 次。这意味着我们只能使用 3 到 5 的表面 1 次。
标签: sql sql-server sqlite cursor