基于小时的分组日期列

Question

我在 sqlite 数据库中有一个表，用于存储有关通话记录的数据。举个例子，假设我的表是这样的

| Calls_count | Calls_duration | Time_slice | Time_stamp |
|    10       |     500        | 21         | 1399369269 |
|     2       |     88         | 22         | 1399383668 |    

这里

Calls_count 是自上次观察以来的通话次数

Calls_duration 是自上次观察以来的通话持续时间，以毫秒为单位

时间片表示一周的时间部分。每天分为 4 部分，每部分 6 小时，这样

     06:00-11:59 | 12:00-17:59 | 18:00- 23.59 | 24:00-05:59 |
Mon| 11          | 12          | 13           | 14          | 
Tue| 21          | 22          | 23           | 24          | 
Wed| 31          | 32          | 33           | 34          | 
Thu| 41          | 42          | 43           | 44          | 
Fri| 51          | 52          | 53           | 54          | 
Sat| 61          | 62          | 63           | 64          | 
Sun| 71          | 72          | 73           | 74          | 

time_stamp 是进行观察/记录插入数据库时​​的 unix 纪元

现在我想创建一个查询，如果我为一周的开始和结束指定 time_stamp，结果是 168 行数据，给我按小时分组的呼叫总和，这样我每天得到 24 行周。这是一周内每小时的通话细分。

SUM_CALLS | Time_Slice | Hour_of_Week |
10        | 11         | 1            |  
0         | 11         | 2            | 
....
7         | 74         | 167          |  
4         | 74         | 168          |  

在上面的预期结果示例中，

    1st row is  Monday 06:00-06:59 
    2nd row is  Monday 07:00-07:59
    Last row is Sunday 04:00-05:59

Answer 1

自 3.8.3 版起 SQLite 支持公用表表达式 这是一个可能的解决方案

WITH RECURSIVE
  hours(x,y) AS (SELECT CAST(STRFTIME('%s',STRFTIME('%Y-%m-%d %H:00:00', '2014-05-05 00:00:00')) AS INTEGER),
                        CAST(STRFTIME('%s',STRFTIME('%Y-%m-%d %H:59:59', '2014-05-05 00:00:00')) AS INTEGER)

            UNION ALL

                SELECT x+3600,y+3600 FROM hours LIMIT 168)

SELECT
        COALESCE(SUM(Calls_count),0) AS SUM_CALLS,
        CASE CAST(STRFTIME('%w',x,'unixepoch') AS INTEGER)
          WHEN 0 THEN 7 ELSE STRFTIME('%w',x,'unixepoch') END
        ||
        CASE
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '06:00:00' AND '11:59:59' THEN 1
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '12:00:00' AND '17:59:59' THEN 2
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '18:00:00' AND '23:59:59' THEN 3
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '00:00:00' AND '05:59:59' THEN 4
        END AS Time_Slice,
        ((x-(SELECT MIN(x) FROM hours))/3600)+1 AS Hour_of_Week

  FROM hours LEFT JOIN call_logs
    ON call_logs.time_stamp >= hours.x AND call_logs.time_stamp <= hours.y
    GROUP BY Hour_of_Week
    ORDER BY Hour_of_Week
    ;

这是用没有 cte 的 SQLite 版本 3.7.13 测试的：

DROP VIEW IF EXISTS digit;
CREATE TEMPORARY VIEW digit AS SELECT 0 AS d UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION
                              SELECT 5      UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
                              ;

DROP VIEW IF EXISTS hours;
CREATE TEMPORARY VIEW hours AS SELECT STRFTIME('%s','2014-05-05 00:00:00') + s AS x,
                                      STRFTIME('%s','2014-05-05 00:00:00') + s+3599  AS y
                                FROM (SELECT (a.d || b.d || c.d) * 3600 AS s FROM digit a, digit b, digit c LIMIT 168)
                                ;

SELECT
        COALESCE(SUM(Calls_count),0) AS SUM_CALLS,
        CASE CAST(STRFTIME('%w',x,'unixepoch') AS INTEGER)
          WHEN 0 THEN 7 ELSE STRFTIME('%w',x,'unixepoch') END
        ||
        CASE
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '06:00:00' AND '11:59:59' THEN 1
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '12:00:00' AND '17:59:59' THEN 2
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '18:00:00' AND '23:59:59' THEN 3
          WHEN STRFTIME('%H:%M:%S',x,'unixepoch') BETWEEN '00:00:00' AND '05:59:59' THEN 4
        END AS Time_Slice,
        ((x-(SELECT MIN(x) FROM hours))/3600)+1 AS Hour_of_Week

  FROM hours LEFT JOIN call_logs
    ON call_logs.time_stamp >= hours.x AND call_logs.time_stamp <= hours.y
    GROUP BY Hour_of_Week
    ORDER BY Hour_of_Week
    ;