无法使用 php mysql 准备好的语句插入 Select 语句

Question

谁能帮我查询mysql。我正在尝试使用插入选择语句插入多行。

if ($insert_stmt = $mysqli->prepare("INSERT INTO order_processing_info (order_id, cart_item_id, item_id, price, quantity) VALUES (?, (SELECT s.cart_item_id, i.item_id, i.price, s.quantity FROM inventory_info AS i, cart_info AS s  WHERE i.item_id=s.item_id AND s.user_id = ?))")) {
                    $insert_stmt->bind_param('ss', $order_id, $user_id);

我认为问题是因为我希望这里所有插入的 order_id 都相同，尽管我不确定。

之前我尝试在 select 语句块中运行它，但没有成功。

if ($select_stmt = $mysqli->prepare("SELECT i.item_id, i.price, s.quantity, s.cart_item_id FROM inventory_info AS i, shopping_cart_info AS s  WHERE i.item_id=s.item_id AND s.user_id = ?")) {
        $select_stmt->bind_param("s", $user_id);
        $select_stmt->execute();
        $select_stmt->bind_result($item_id, $price, $quantity, $cart_item_id);

        while ($select_stmt->fetch()) {

            if ($insert_stmt = $mysqli->prepare("INSERT INTO order_processing_info (order_id, cart_item_id, item_id, price, quantity) VALUES (?, ?, ?, ?, ?)")) {
                $insert_stmt->bind_param('sssss', $order_id, $cart_item_id, $item_id, $price, $quantity);
                // Execute the prepared query.
                if (!$insert_stmt->execute()) {
                    header('Location: ../error.php?err=INSERT failure: INSERT');
                    exit();
                }
            }
        }
        $select_stmt->close();
    }

我在stackoverflow上查了很多，但我想我对数据库查询不是很精通，所以如果有人能帮助我，我将不胜感激。

Answer 1

使用“INSERT INTO SELECT”查询（http://www.w3schools.com/sql/sql_insert_into_select.asp），此时只需绑定一个参数，即用户 ID。它还可以节省循环中查询的开销