使用查找表 SQL 将 3 个 sql 视图合并为 1 个查询

Question

我需要将 3 个不同查询的估计时间分钟加到 1 个 sql 查询中。 我有 3 个视图（一个用于在机器 A 上按作业切割的零件，一个用于在机器 B 上按作业切割的零件，以及在机器 C 上按作业切割的零件）。我有另一个表，其中列出了所有具有估计切割时间的零件，我们将其称为 TableA。我已经编写了三个不同的查询，使用将连接留在 TableA 上的视图来汇总切割时间。但是，我想要一个查询，该查询返回一个表，其中包含作业列表和机器每个作业的估计切割时间。因此，每一行都会有工作，然后是每台机器分解的三个估计切割时间。

 --------Machine A-------
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineA.JobNum
 FROM MachineA
 LEFT JOIN TableA on
 TableA.Part = MachineA.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineA.Job

 --------Machine B-------
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineB.JobNum
 FROM MachineB
 LEFT JOIN TableA on
 TableA.Part = MachineB.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineB.Job

 --------Machine C-------
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineC.JobNum
 FROM MachineC
 LEFT JOIN TableA on
 TableA.Part = MachineC.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineC.Job

我正在寻找的示例表

 Job | MachinA_Time | MachineB_Time | MachineC_Time|
 ----------------------------------------------------
 123 | 345          | 512           | 452          |
 124 | 215          | 351           | 356

Answer 1

使用UNION，您可以这样做：

SELECT JobNum
  ,MAX(MachinA_Time) AS MachinA_Time
  ,MAX(MachinB_Time) AS MachinB_Time
  ,MAX(MachinC_Time) AS MachinC_Time
FROM
(

    SELECT MachineA.JobNum, sum(TableA.[minutes]) as MachinA_Time, NULL AS MachinB_Time, NULL AS MachinA_Time
     FROM MachineA 
    LEFT JOIN TableA on TableA.Part = MachineA.PART
     WHERE TableA.OP = 10 and OP_DISABLE IS NULL
     group by MachineA.Job
    UNION ALL
     SELECT MachineB.JobNum, NULL, sum(TableA.[minutes]), NULL
     FROM MachineB
     LEFT JOIN TableA on
     TableA.Part = MachineB.PART
     WHERE TableA.OP = 10 and OP_DISABLE IS NULL
     group by MachineB.Job
    UNION ALL
     SELECT MachineC.JobNum, NULL, NULL, sum(TableA.[minutes])
     FROM MachineC
     LEFT JOIN TableA on
     TableA.Part = MachineC.PART
     WHERE TableA.OP = 10 and OP_DISABLE IS NULL
     group by MachineC.Job

) AS t
GROUP BY JobNum

Answer 2

我认为您可以通过使用条件聚合和 UNION 来节省不必要的连接，因为格式是相同的

SELECT p.jobnum,
       SUM(CASE WHEN t.machine = 'A' THEN t.[minutes] END) as machineA_Time,
       SUM(CASE WHEN t.machine = 'B' THEN t.[minutes] END) as machineB_Time,
       SUM(CASE WHEN t.machine = 'C' THEN t.[minutes] END) as machineC_Time
FROM(SELECT s.minutes,s.part,'A' as machine FROM MachineA s
     UNION ALL 
     SELECT s.minutes,s.part,'B' FROM MachineB s
     UNION ALL 
     SELECT s.minutes,s.part,'C' FROM MachineC s) t
JOIN TableA p
 ON(p.part = t.part)
WHERE p.op = 10
GROUP BY p.jobnum

这个查询可能需要一些额外的调整，因为我不知道OP_DISABLE IS NULL来自哪里。

Answer 3

只需根据共享作业加入每个结果#：

WITH MachineA
AS
(
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineA.JobNum
 FROM MachineA
 LEFT JOIN TableA on
 TableA.Part = MachineA.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineA.Job
 ),
 MachineB
 as
 (-
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineB.JobNum
 FROM MachineB
 LEFT JOIN TableA on
 TableA.Part = MachineB.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineB.Job
 ),
  MachineC
 as
(
 SELECT 
 sum(TableA.[minutes]) as 'total', MachineC.JobNum
 FROM MachineC
 LEFT JOIN TableA on
 TableA.Part = MachineC.PART
 WHERE TableA.OP = 10 and OP_DISABLE IS NULL
 group by MachineC.Job
 )

 SELECT A.JobNum as Job, MachineA.total as MachineATime,  MachineB.total as MachineBTime, MachineC.total as MachineCTime
 FROM MachineA as A
 INNER JOIN MachineB as B
 ON B.JobNum = A.JobNum
 INNER JOIN MachineC as C
 ON C.JobNum = A.JobNum