【发布时间】:2019-08-30 07:10:07
【问题描述】:
我想使用 Python sqlite 模块将记录插入到 sqlite 数据库中。
使用 executemany() 执行 INSERT 语句会导致“参数类型不受支持”错误。
import sqlite3
conn = sqlite3.connect('food.db')
c = conn.cursor()
c.execute('''CREATE TABLE IF NOT EXISTS nutritional_values
(item, calories, total fat, protein)''')
items = [ ('Broccoli Chinese', 22, 0.7, 1.1),
('chia seeds', 490, 30.8, 15.6),
('blueberries', 57, 0.3, 0.7),]
c.executemany('INSERT INTO nutritional_values VALUES (?,?,?,?)',items)
c.execute('''CREATE TABLE IF NOT EXISTS food_consumption
(date, item, amount)''')
c.execute('DELETE FROM food_consumption')
consumed = [ ('24/8/2019', 'Broccoli Chinese', 1.5),
('24/8/2019', 'chia seeds', 0.35),
('24/8/2019', 'blueberries', 0.4),]
c.executemany('INSERT INTO food_consumption VALUES (?,?,?)',consumed)
sql = """SELECT nv.item, nv.calories
FROM nutritional_values nv
INNER JOIN food_consumption fc
ON nv.item = fc.item"""
for row in c.execute(sql):
print(row)
c.execute('''CREATE TABLE IF NOT EXISTS nutrition_consumed
(var1)''')
for row in c.execute(sql):
var1 = row[1]*2
item = [(var1),]
c.executemany('INSERT INTO nutrition_consumed VALUES (?)', (item),)
for row in c.execute('SELECT * FROM nutrition_consumed'):
print(row)
conn.commit()
conn.close()
得到
c.executemany('INSERT INTO nutrition_consumed VALUES (?)', (item),)
ValueError: parameters are of unsupported type
如何将var解析到表中?
【问题讨论】:
-
(item)应该是(item,)以使其成为一个元组。 -
好的已更正,但这不会改变错误
-
我说的是
(item,)而不是(item),