SQL 语句中变量方程放在哪里？

Question

我正在使用 MS Access 运行一些计算。以下是给我带来麻烦的整体代码：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _
SELECT ?, ?, (M * 0) + B _AS Tier_Juncture_1, _
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth)) / (StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _
FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B, _
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M, _
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _
" & On_Statement & "", con)
    cmd3.Parameters.AddWithValue("@Calculation", Calculation)
    cmd3.Parameters.AddWithValue("@[Interval]", Interval)
    cmd3.ExecuteNonQuery()

更具体地说，我的目标是将这个公式的结果插入到我名为Criteria 的表中Tier_Juncture_1 字段中：

(M * 0) + B _AS Tier_Juncture_1

如您所见，我在这个等式中有两个变量，M 和 B。以下是每个公式：

(Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B

(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M

我的问题是，在我的 SQL 语句中，我是否将我的两个变量的公式放在我原来的 Tier_Juncture_1 公式可以使用这些变量？正如您在上面看到的，我试图将它们放在我的 FROM 子句中，但我收到了这个错误：Syntax error in FROM clause.

变量本身的公式应该没有任何问题。我已经独立测试了它们，它们都返回正确的值而没有错误。我只需要知道将它们放在我的 SQL 语句中的什么位置。

更新

根据以下建议，我已从我的 SQL 语句中删除了参数。现在看起来像这样：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _
SELECT " & Calculation & ", " & Interval & ", (M * 0) + B AS Tier_Juncture_1, _
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth)) / (StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _
FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B, _
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M, _
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _
" & On_Statement & "", con)
    cmd3.ExecuteNonQuery()

但是当我运行它时，我收到以下错误：Syntax error in FROM Clause.

我相信我收到了这个错误，因为我从原始帖子中插入了变量 M 和 B 的方程式。所以我的问题仍然存在。在我的 SQL 语句中，我应该将这些等式放在哪里。

第二次更新

这是Debug.Writeline(cmd3.CommandText)返回的SQL语句：

INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) SELECT Current_Ratio, MRQ, (M * 0) + B AS Tier_Juncture_1, ((Avg(C.Current_Ratio * G.Growth) - Avg(C.Current_Ratio) * Avg(G.Growth)) / (StDevP(C.Current_Ratio) * StDevP(G.Growth)) * 10) AS Weight FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C.Current_Ratio) / Count(*))) AS B, (Sum(C.Current_Ratio * G.Growth) - ((Sum(C.Current_Ratio) * Sum(G.Growth)) / Count(*))) / (Sum(C.Current_Ratio * C.Current_Ratio) - ((Sum(C.Current_Ratio) * Sum(C.Current_Ratio) / Count(*)))) AS M, Current_Ratio AS C INNER JOIN Quarterly_Growth_Rates AS G ON (C.Ticker = G.Ticker) AND ((IIF(C.Period = 4, C.Year + 1, C.Year)) = G.Year) AND ((IIF(C.Period = 4, 1, C.Period + 1)) = G.Qtr)

Answer 1

为了在您的 SQL（即Avg(G.Growth)）中返回非聚合字段和聚合函数，您必须提供 GROUP BY。

通过查看您的代码，我知道 Calculation 不是聚合，因为您对字段和表名使用相同的变量。

如果您需要进一步的帮助，您需要提供生成的 SQL 以供检查，我们不知道您的变量中有什么。即，Debug.Writeline(cmd3.CommandText)