【发布时间】:2013-10-28 05:27:45
【问题描述】:
我有一个现有的 SQL 查询,我现在想使用 GroupBy,但出现错误:无法对包含聚合或子查询的表达式执行聚合函数。
我的场景说明:
我的主表 (dbo.DataLog) 包含 3 列,TimestampUTC、MeterTagId、Data。
数据通常每隔 15 分钟输入一次,我有很多仪表 (MeterTagId) 时间戳UTC。 Data 列是一个浮点数,这是一个累加值。即要获得一个仪表周期的实际值,我需要从当前值中减去最后一个值。在此之前,我已成功查询单个仪表,但现在我尝试按时间分组并显示该时间所有仪表的总和/总计。
原始工作非求和查询:
SELECT
l.TimestampUTC
-- Get this value minus the last value
,(SELECT (l.[Data] -
( SELECT TOP 1 l2.Data
FROM [DataLog] l2
WHERE l2.MeterTagId = l.MeterTagId
AND l2.TimestampUTC < l.TimestampUTC
ORDER BY l2.TimestampUTC DESC)
)
) AS Actual_Value
FROM [dbo].[DataLog] l
INNER JOIN [dbo].MeterTags t on t.MeterTagId = l.MeterTagId
INNER JOIN [dbo].Meters m on m.MeterId = t.MeterId
INNER JOIN [dbo].GroupsMeters gm on gm.MeterId = m.MeterId
INNER JOIN [dbo].Groups g on g.GroupId = gm.GroupId
LEFT OUTER JOIN dbo.Units u on u.UnitId = t.UnitId
WHERE (@MeterId is null OR M.MeterId in (@MeterId))
AND (@MeterTagId is null OR t.MeterTagId in (@MeterTagId))
AND (@StartDate is null OR l.TimestampUTC >= @StartDate)
AND (@EndDate is null OR l.TimestampUTC <= @EndDate)
AND (@GroupId is null OR g.GroupId in (@GroupId))
.
我尝试获取摘要:
SELECT
l.TimestampUTC
-- Get this value minus the last value
, (SELECT SUM(l.[Data] -
( SELECT TOP 1 l2.Data
FROM [DataLog] l2
WHERE l2.MeterTagId = l.MeterTagId
AND l2.TimestampUTC < l.TimestampUTC
ORDER BY l2.TimestampUTC DESC)
)
)AS Actual_Value
FROM [dbo].[DataLog] l
INNER JOIN [dbo].MeterTags t on t.MeterTagId = l.MeterTagId
INNER JOIN [dbo].Meters m on m.MeterId = t.MeterId
INNER JOIN [dbo].GroupsMeters gm on gm.MeterId = m.MeterId
INNER JOIN [dbo].Groups g on g.GroupId = gm.GroupId
LEFT OUTER JOIN dbo.Units u on u.UnitId = t.UnitId
WHERE (@MeterId is null OR M.MeterId in (@MeterId))
AND (@MeterTagId is null OR t.MeterTagId in (@MeterTagId))
AND (@StartDate is null OR l.TimestampUTC >= @StartDate)
AND (@EndDate is null OR l.TimestampUTC <= @EndDate)
AND (@GroupId is null OR g.GroupId in (@GroupId))
AND t.Name ='Real Energy Net'
GROUP BY l.TimestampUTC
我已阅读此处的其他帖子,但无法理解所需的逻辑,我想/希望这是 sql 开发人员经常遇到的问题?谢谢!
【问题讨论】:
标签: sql sql-server group-by